argon atom
No element has the exact same election arrangement as another element. However ion can have the same election arrangement as another element. For example Chloride (Cl-) has the same configuration as Argon, and Potassium (I) (K+) also has the same configuration as argon.
Phosphorus has an electron configuration of 1s2 2s2 2p6 3s2 3p3. Another way to write that is [Ne] 3s2 3p3. The [Ne] represents the fact that the beginning of phosphorus' electron configuration is the same as Neon's.
argon
Considering the normal calcium ion Ca2+ it has the same electronic configuration as the noble gas Argon.
in the same way as sodium/potassium forms an ion. Lithium has an electron configuration of 2,1 Sodium has an electron configuration of 2,8,1, Potassium has an electron configuration of 2,8,8,1 Rubidium has an electron configuration of 2,8,8,18,1 Caesium has the electron configuration of 2,8,8,18,18,1 Notice in all cases the last number is '1'. This represents the outer most electron, shell with one electron. Since it is the outer most electron and is shielded by energy shells of electrons from the nucleus, this outer most electron is not strongly held to the atom. The atom readily releases this outermost electron , and the process is called ionisation. Chemically it is represented by the formula M(g) = M^+(g) + e^- NB 'M' is an ATOM 'M^+' is an ION (Not an atom).
Potassium must lose one electron (to have the same configuration as the noble gas argon), and fluorine must gain one electron (to have the same configuration as neon)
No element has the exact same election arrangement as another element. However ion can have the same election arrangement as another element. For example Chloride (Cl-) has the same configuration as Argon, and Potassium (I) (K+) also has the same configuration as argon.
No. No two elements have the same electron configuration.
Because each of them can form a cation with the electron configuration of a noble gas by donating one electron to another element.
The ions of elements nitrogen (N3-), oxygen (O2-), and fluorine (F-) will have the same electron configuration as a sodium ion (Na+), which is the same as the electron configuration of the noble gas neon.
A potassium atom "always" loses exactly one valence electron when it reacts with another element, because one valence electron in a potassium atom has a much lower ionization energy requirement than any other electron in the same atom. (This property is generally ascribed to the fact that when a potassium loses exactly one electron, it acquires the very stable electron configuration of the noble gas argon.) A chlorine atom has a very strong attraction (its electronegativity) for exactly one electron, which gives the charged atom the electron configuration of an argon atom. Therefore, when a potassium atom is close enough to a chlorine atom, one electron is transferred between to form an ionic bond and a formula unit of the compound potassium chloride.
The answer is nitrogen. Nitrogen is one example of an element that has the same valence electron configuration as phosphorus.Ê
Mg 2+ Has the same electron configuration as neon. Two electrons lost to do this.
The answer is nitrogen. Nitrogen is one example of an element that has the same valence electron configuration as phosphorus.Ê
N3- , O2- , F- , Na+ , Mg2+ , Al3+ all have the same electron configuration as Neon.
It has the same electron configuration as in a neon atom.
102 ( the atomic #, # of protons, and #of electrons are always the same )