Yes.. My bottled spiked eggnog has frozen at 15% alcohol by volume.
About 23 degrees Fahrenheit
600ml.
The concentration of the diluted solution will be 15(300/1000) = 4.5 %, if the percent is expressed on a weight/volume basis.
Make an equation: x(.10) = 50gal(.15) Solve algebraically: x = 75 gal
Adding salt to water increases its density and lowers its freezing point. ---------------------- I've just completed a repeated experiment on the effects of salt and the freezing point of water. A saturated salt solution will not freeze at -15 degrees Celsius (my freezer temperature). At exactly -21.1 degrees Celsius the salt begins to crystallize out of the solution, along with the ice, until the solution completely freezes.
60 g/400 g (x100%) = 15% (w/w) calcium chloride
That all depends on what you want the final concentration of alcohol to be.
Let a be the number of ounces of 25% alcohol required. Then, 25a + (30x9) = 28(9 + a) 25a + 270 = 252 + 28a 3a = 18 a = 6 Then 6 ounces of 25% alcohol + 9 ounces of 30% alcohol produces 15 ounces of 28% alcohol.
You have 6 litres of alcohol in 24 litres of water You need to add x litres to make 6 equal to 15% of 30 + x. 6 is 15% of 40, so x = 10
To make 15% alcohol from 40% alcohol you simply take 15cc of your 40% alcohol and put it into a graduated cylinder and fill the cylinder up the rest of the way with deionised water or distilled water to the 40cc mark on the graduated cylinder. you will then have 15% alcohol from 40%
Mixing 80 liters of 15% solution and 520 liters of 90% solution will give 600 liters of 80% solution.
600ml.
1.5 pints
The concentration of the diluted solution will be 15(300/1000) = 4.5 %, if the percent is expressed on a weight/volume basis.
over 15
Most use a 15% alcohol to 85% gasoline mixture.
Make an equation: x(.10) = 50gal(.15) Solve algebraically: x = 75 gal
15%