unobtainium
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That is highly dependent on the cluster size of the transition metal.
For example:
a) Dissolve gold in aqua regia, this will create gold clusters of some hundred to some thousand gold atoms. If you precipitate it with NaOh the precipitate is brown.
b) Dissolve gold in aqua regia, get rid of the nitric acid by repeated evaporation with HCl - Boil the solution a long time in HCl - You will end up with Au2Cl6 - This will form a orangish red precipitate...
c) Dissolve gold in aqua regia, get rid of the nitric acid by repeated evaporation with HCl - Boil the solution a long time in HCl and NaCl (1 mol of gold to 20 mol of NaCl) - The color of the gold clorid will turn green and you will end up with NaAuCl3 - Use nitric acid to get rid of the clorid - you end up with NaAu - raise the ph to exact 7 (with NaOH)and you will end up with HAu which forms a white precipitate - anneal the HAu ander innert gas to get pure monoatomic Au a white powder.
Fazit: the world of microclusters is strange...
Sodium hydroxide (NaOH) is an insoluble base that can be used to make copper sulfate. When sodium hydroxide is added to a solution of copper sulfate, a blue precipitate of copper hydroxide forms. This precipitate can be filtered and then reacted with sulfuric acid to produce copper sulfate.
Metallic copper does not react with sodium hydroxide. But if sodium hydroxide is added into a solution of copper ions, it would form Copper(II) Hydroxide. It is a precipitate which is insoluble in water.
They are not soluble, therefore they do not precipitate or form a color....a.k.a....no reaction...
When sodium hydroxide reacts with magnesium sulfate, a double displacement reaction occurs where the sodium ions from sodium hydroxide switch places with the magnesium ions from magnesium sulfate to form sodium sulfate and magnesium hydroxide. The products of this reaction are aqueous sodium sulfate and a white precipitate of magnesium hydroxide.
Magnesium Hydroxide since in the Solubility Rules it states that "All hydroxides are insoluable exceptcompounds of the alkali metals, Ca2+, Sr2+ and Ba2+" and since Magnesium is not in any one of those on the list Hydroxide is insoluable and therefore the precipitate.
Mixing sodium hydroxide and calcium nitrate will not form a precipitate. Instead, it will form solutions of sodium nitrate and calcium hydroxide.
Sodium hydroxide (NaOH) is an insoluble base that can be used to make copper sulfate. When sodium hydroxide is added to a solution of copper sulfate, a blue precipitate of copper hydroxide forms. This precipitate can be filtered and then reacted with sulfuric acid to produce copper sulfate.
When sodium hydroxide is added to copper sulfate, a chemical reaction occurs where a blue precipitate of copper hydroxide is formed. This can be further reacted to form copper oxide if heated strongly. The remaining solution will be sodium sulfate.
Metallic copper does not react with sodium hydroxide. But if sodium hydroxide is added into a solution of copper ions, it would form Copper(II) Hydroxide. It is a precipitate which is insoluble in water.
The precipitate formed when barium chloride reacts with sodium hydroxide is barium hydroxide (Ba(OH)2).
Beryllium hydroxide
When sodium hydroxide is added to copper oxide, a blue precipitate of copper hydroxide is formed. The color of the precipitate is due to the formation of copper ions in solution.
The precipitate formed when a calcium salt reacts with sodium hydroxide solution is white. This white precipitate is calcium hydroxide, which is sparingly soluble in water.
When copper sulfate is added to sodium hydroxide, a blue precipitate of copper hydroxide is formed. The color change observed is from the initial blue color of copper sulfate to the blue precipitate of copper hydroxide.
They are not soluble, therefore they do not precipitate or form a color....a.k.a....no reaction...
When sodium hydroxide reacts with magnesium sulfate, a double displacement reaction occurs where the sodium ions from sodium hydroxide switch places with the magnesium ions from magnesium sulfate to form sodium sulfate and magnesium hydroxide. The products of this reaction are aqueous sodium sulfate and a white precipitate of magnesium hydroxide.
Answer: Cupric hydroxide (as bluish white precipitate) and sodium nitrate. Cu(NO3)2 + 2NaOH --> Cu(OH)2 + 2NaNO3