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Boron

doesn't follow the octet rule in that many of its compounds are electron deficient. The B has 3 valence electrons

and each F has 7 valence electrons, so 3*7=21+3 is 24 valence electrons in total. As the Lewis diagram will reveal, the B is connected to 3 atoms

and has no lone pairs, thus sp2.


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Q: What type of hybrid orbitals form by the boron atom in a molecule of boron fluoride?
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