You asked what would happen to your weight if the earth's mass doubled (due to a density increase) without changing in size.
There are three very useful equations in this context.
First, weight = mass * gravity.
Second, force = mass * acceleration.
Third, gravity = (g-constant (your mass * earth's mass))/distance between the masses squared.
It happens that the first two equations mean the same thing. For this to be true, weight would have to be a force (it is, and it's called "newtons"), and gravity would have to be an acceleration (that's also true).
So what we need to do here is figure out how much gravity the earth would have if its mass doubled. Since the earth does not change in size, in your problem, the distance doesn't either. We can then set distance = 1 in the third equation. Likewise, the gravitational constant doesn't change; that's why it's called a "constant".
So what do we have? It's clear that the gravity acting on you and earth doubles if we do nothing but double the earth's mass.
Since your weight = your mass times gravity, and gravity has doubled as we've shown, the answer is simple: YOUR WEIGHT WOULD DOUBLE TOO.
109 Actually, no. 109 would probably be for Jupiter. For Earth, hundreds of Earth's surface could fit in the sun's radius.
Mars's gravitational pull is 38% that of Earth's, meaning you would weigh 38 pounds on that planet.
gravitational field strength on Earth= 9.8 m/s^2.: 70 * 9.8= 686 N
It would go something like this. e = Earth's gravity m = Mercury's gravity e*0.38=m Just put whatever number in Earth's gravity and do the math.
You would weigh more on Earth than on the Moon. This is because weight is a measure of the force of gravity acting on an object, and the gravitational pull on Earth is stronger than on the Moon.
i will be twice as heavy
Yes, in a way. If the radius of the Earth decreased but it's mass stayed the same, then the forces "pulling" on you (weight) would increase and you would be heavier. If the radius of the Earth increased and the mass stayed the same, then you would be lighter. You would actually weigh less on the top of Mount Everest than on the beach of Honolulu. BTW: This is not a good idea for a weight loss program.
weight on jupiter=((mass of jupiter)*(Radius of earth)2/(mass of earth)*(Radius of jupiter)2)*weight on earth
It would double.
It would double.
On the new planet, Sara would weigh 400 lbs. This is because weight is proportional to the mass of the planet and inversely proportional to the square of the radius. Since the new planet is 5 times larger in radius, the weight would increase by a factor of 5^2 = 25.
That would depend on the planet's radius. The strength of gravity depends on both the mass of the object in question and the distance from its center of mass. If the planet in question had the same radius as Earth, then the person would weigh 200 lbs as gravity would be twice as strong. If the planet had the same density as Earth it would have 1.26 times Earth's radius and gravity would be 1.26 times as strong and the person would weigh 126 lbs. If the planet had about 1.41 times Earth's radius then that person's would weight 100 lbs.
Nothing, as not volume, but mass exercises gravity. For example: Black holes somethimes are alot smaller than actual suns, but still they have an enormous gravitational force, this is because a black hole has an extremely high density, so it needs less volume to exercise the same force.
The idea is to calculate Earth's surface area, using the formula for the area of a sphere. Then multiply pressure times area, to get force. The weight of the atmosphere is simply the force with which it presses down upon Earth.
That would depend on what happened to the Earth's radius as well, since gravity depends on the mass of the object and the square of the distance between them. So if the mass were doubled and the radius of the Earth also doubled, the force of gravity would actually go down by half!
That would be the radius of the earth which is:6,378.1 kilometers
The alkali earth metal with the smallest atomic radius would be beryllium(Be), number four