What would happen to the rate of a reaction with rate law kNO2H2 if the concentration of NO were doubled?

Answer 1

The rate would be four times larger

Answer 2

The rate of reaction is directly proportional to the concentration of the reactant. Therefore, when the concentration doubles so should the rate. This is because there are more particles which are crowded close together, meaning they will collide more often (and more successfully) and therefore increasing the rate of reaction.

Answer 3

If the concentration of NO were doubled in the rate law k[NO]^2[H2], the rate of the reaction would increase by a factor of 4 (2^2). This is because the rate of the reaction is directly proportional to the square of the concentration of NO.

Answer 4

The rate of reaction is also decreased.

Answer 5

the rate would be four times larger. apex

Answer 6

quadrupled