wouldn't it be more than 1 g? i say this because the first substance that the oxygen would chemically combine to would have its own mass (1g), and once the oxygen combines to it, wouldn't the mass of the oxygen and the substance also combine, forming a new mass greater than 1 g?
metal sulfreid will turn in to tast
ammonium carbonate
The mass is 991,5 g.
Formula of first oxide = M3O4 let mass of the metal be == x percentage of metal in M3O4 = (3x/ 3x+64) *100 but % age = (100-27.6) = 72.4 % so, (3x/ 3x+64)*100 = 72.4 or x = 56. in 2nd oxide, oxygen = 30%....so metal = 70% so, ratio :-- M : O 70/56 : 30/16 1.25 : 1.875 2 : 3 so, 2nd oxide = M2O3
I don't know the method, but here is the link to the Beryllium Oxide Properties
What metal?
Na2O + H2O ---> 2NaOH this is a metal oxide (base) reacting with water to form an alkali. Mass of NaOH is 40
In higher oxide Metal = 80% Oxygen = (100-80)% = 20% Therefore, we can say that 4 parts of metal combines with 1 part of oxygen. Now, 0.72 g of lower oxide on oxidation gives 0.8 g of higher oxide. It can be assumed that the mass percent of metal in 0.8 g is same as that of 0.72 g of lower oxide. So, Mass of metal in higher oxide = (80/100) x 0.8 g = 0.64 g If in 0.8 g of higher oxide 0.64 g is metal then mass of oxygen present in higher oxide will be (0.8 - 0.64) g = 0.16 g Since, lower oxide contains the same mass of metal as that of higher oxide, we need to calculate the mass of oxygen in lower oxide. Mass of oxygen in lower oxide = (0.72-0.64) g = 0.08 g According to Law to multiple proportions if two elements combine with each other to form two different compounds then the ratio of masses of that element which combines with the other element whose mass is fixed in both the compounds, will be in small whole numbers. Now, in the given problem the mass of metal in both the oxide is fixed so, for the data to illustrate the law of multiple proportion the ratio of mass of oxygen in both the oxides should be in whole numbers. Now, mass of oxygen in higher oxide : mass of oxygen in lower oxide = 0.16 : 0.08 = 2 : 1. Therefore, it can be said that the given data depicts law of multiple proportion.
Manganese (Mn)
metal sulfreid will turn in to tast
6g
ammonium carbonate
Depends on what oxide
2. beryllium oxide. Each oxide contains as many oxygen atoms as alkaline earth metal atoms, and beryllium has the smallest atomic weight of the alkaline earth metals. Therefore, beryllium oxygen has the greatest percentage by weight of oxygen.
Calculate the mass of Oxygen in the tin oxide
When a magnesium strip is heated strongly in air, it undergoes a chemical reaction called oxidation. Magnesium reacts with oxygen in the air to form magnesium oxide. The mass of the strip increases because magnesium combines with oxygen atoms from the air to form a heavier compound (magnesium oxide).
The mass of lithium oxide (Li2O) is 8,o9 g.