q( Joules) = mass grams * specific heat * change in temperature
90 kj = 90000 Joules
2 kg = 2000 grams
90000 Joules = (2000 g)( SP )(200 C - 80 C)
90000 = 240000(SP)
0.375 J/gC
( The actual specific heat of copper is 0.385 J/gC, so close enough for the problem type )
O.39
None. Changing water from 25 degrees C to 5 degrees C requires heat to be REMOVED, not added!
It gets colder and freezes Actually it first freezes then it gets colder only after it is all frozen.
When you touch some ice, a lot of heat from your skin is first needed to melt the ice. This so-called phase-transition requires a relatively large amount of heat. Once molten, the resulting liquid water will still be 0 deg C, so at that point you have already lost a lot of heat and still have to heat up the 0 deg C water, hence ice appears colder.
LATENT HEAT OF FUSION When one pound of ice melts, it absorbs 144 BTUs at a constant temperature of 32°F. If one pound of water is to be frozen into ice, 144 BTUs must be removed from the water at a constant temperature of 32°F.
You can measure relative heat with a thermometer.The units of temperature (degrees Celsius / kelvins) indicate molecular heat content, while the actual heat energy being generated, added, or removed is measured in joules(newton-meters), a unit of work.
The temperature at which no more energy can be removed from a substance is absolute zero, which is 0 Kelvins or -273.15 degrees Celsius.
6.276 kJ
6.276 kJ
-273.15 degrees Celsius (-459.67 degrees Fahrenheit) is the temperature at which no more energy can be removed from matter.It is called Absolute Zero and marks the 0 for the Kelvin and Rankine scale.
-273.15 degrees Celsius (-459.67 degrees Fahrenheit) is the temperature at which no more energy can be removed from matter.It is called Absolute Zero and marks the 0 for the Kelvin and Rankine scale.
There are no units for the temperature. The temperature change could be 230 Celsius degrees or 170 Fahrenheit degrees (94 Celsius degrees). In fact they could be in less commonly used units: eg Reaumur.
That sounds like a description of the temperature known as "absolute zero". This temperature is zero kelvin; it is also approximately -273 degrees Celsius.
0.385 Joules/Gram Celsius is the specific heat of copper. So, q(Joules) = mass * specific heat * change in temperature q = (200 g Cu)(0.385 J/gC)(30 C - 150 C) = - 9240 Joules -------------------------amount of heat dissipation ( answer can be positive )
E = mass x sp ht x Δ°tIn order to calculate the final temperature change, we must also find the temperature change.1. Find the temperature change.Divide joules by (mass x specific heat).Δ°t = 40,000J/500.0g x 4.184J/g°CΔ°t = 19.1°C2. Calculate the final temperature.Tf = 10.0 - 19.1Tf = -9.1°CThere was a decrease in temperature, indicating that it was an endothermic reaction (as energy was removed as stated in the question).
This is because the ice at 0 deg C is colder to the extent that the latent heat of freezing has been removed from the water at 0 deg C.
If you can find a block of ice at 25ºC ... or even a picture or a folk legend of one ... I'll go look up the conversion of joules to calories and work this out for you.
The boiling point of pure water is typically about 100 degrees Celsius. This value can vary based on factors such as pressure. Additionally, impurities in a sample of water can alter its boiling point.