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CuCl2(aq) + K2S(aq) --> CuS(s) + 2KCl(aq)

K and Cl are spectators so the net ionic would be:

Cu2+(aq) + S2-(aq) --> CuS(s)

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Q: When a solution of copper II chloride is added to a solution of potassium sulfide a double replacement reaction occurs and forms a black precipitate write an equation for the exchange of Ions?
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How can you make potassium chloride precipitate?

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