CuCl2(aq) + K2S(aq) --> CuS(s) + 2KCl(aq)
K and Cl are spectators so the net ionic would be:
Cu2+(aq) + S2-(aq) --> CuS(s)
When you add calcium chloride to potassium carbonate the products will be solid calcium carbonate and aqueous potassium chloride. The chemical equation for this reaction is CaCl2(aq) + K2CO3(aq) --> 2KCl(aq) + CaCO3(s). This type of reaction is called a double replacement/displacement reaction.
Potassium + Chlorine --> Potassium Chloride (potassium plus chlorine arrow potassium chloride)
2K+Cl2------->2KCl
s + p =
2KBr + Cl2 ----> 2KCl + Br2
You can make potassium chloride precipitate by adding silver nitrate (AgNO3). The chemical equation being AgNO3(aq)+ KCl(aq) = KNO3(aq) + AgCl(s) You know that silver nitrate will form a precipitate as you can see this on a solubility chart.
When you add calcium chloride to potassium carbonate the products will be solid calcium carbonate and aqueous potassium chloride. The chemical equation for this reaction is CaCl2(aq) + K2CO3(aq) --> 2KCl(aq) + CaCO3(s). This type of reaction is called a double replacement/displacement reaction.
Potassium + Chlorine --> Potassium Chloride (potassium plus chlorine arrow potassium chloride)
The balanced equation for copper(II) oxide and potassium chloride is CuO + 2KCl → CuCl2 + K2O When copper(II) oxide reacts with potassium chloride then it forms copper(II) chloride and potassium oxide.
The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4
Worded Equation; Potassium Iodide + Calcium Chloride ------> Potassium Chloride + Calcium Iodide Chemical Equation; KI (l) + CaCl (l) -----> KCl (aq) + Ca(I)2 (aq) Note Answer is only correct if proper states are applied and used.
2K + Cl2 ---> 2KCl
It is impossible to balance that equation.
KCl will not decompose
my answer is on the ionic liquids
4KClO3= 3KClO4+KCl
2K+Cl2------->2KCl