228.8 g of CO2
228.8 g
Its hard to tell from the way you wrote it, but if its supposed to be CaCo3---> CaO + CO2, then CaCo3 is the reactant and CaO and CO2 are the products. Its simply that the elements on the left of the arrow are reactants and the ones on the right are products.
The molar mass of CaCO3 is 100.09 g/mol, and the molar mass of CO2 is 44.01 g/mol. By using stoichiometry, you can calculate that 15.2 grams of CaCO3 would produce 6.51 grams of CO2. Using the ideal gas law, you can then convert the mass of CO2 to volume using its molar volume at STP (22.4 L/mol). The volume of CO2 produced would be around 3.32 liters.