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The element with a valence electron configuration of ns2 np4 is sulfur (S). Since it needs to gain 2 electrons to achieve a stable electron configuration, it is most likely to form an ion with a charge of -2.
Sodium (Na) is the element that would most likely form an ionic compound with fluorine (F). Sodium readily gives up an electron to fluorine to achieve a stable electron configuration, forming sodium fluoride (NaF) which is an ionic compound.
The single "most likely" element that would form an ionic compound with fluorine is cesium, or possibly francium if enough of it could be collected. This is because cesium, among stable elements, has the lowest electronegativity and fluorine has the highest electronegativity. However, any alkali or alkaline earth metal element in fact readily forms an ionic compound with fluorine, as do many other metals.
The element E is likely barium (Ba), as its electron configuration is Kr 5s2. The fluoride compound of barium would be BaF2, with barium losing its two valence electrons to form a 2+ cation and fluoride gaining one electron to form a 1- anion.
The element that is most likely to be reduced is the element that has the highest reduction potential (E°) in a given redox reaction. The element with a more positive reduction potential is more likely to undergo reduction.
Francium (Fr)
Arsenic.
The element with the atomic number 17, which is chlorine, would most likely have the Lewis dot symbol because it typically gains one electron to achieve a stable electron configuration.
Barium (Ba) is the element in group 2 that is most likely to lose an electron, as it is the most reactive element in this group due to having the lowest ionization energy. This makes it easier for barium to lose its outermost electron to form a 2+ cation.
The element with a valence electron configuration of ns2 np4 is sulfur (S). Since it needs to gain 2 electrons to achieve a stable electron configuration, it is most likely to form an ion with a charge of -2.
The element most likely to form an anion is Cl (chlorine). This is because chlorine has a high electronegativity and tends to gain an electron to achieve a stable electron configuration, forming the chloride ion (Cl-).
Lithium is a highly reactive element because it has a single electron in its outer shell, making it eager to donate that electron to achieve a stable electron configuration. This property allows lithium to readily form compounds with other elements.
which of these is an extensive property of a substance? is it color, hardness, malleability, or volume
Chlorine (Cl) would most likely have a positive electron affinity. Typically, elements with high electron affinities are found on the right side of the periodic table, closer to the noble gases. Among the choices given, Argon (Ar) is a noble gas and has a positive electron affinity.
Sodium (Na) is the element that would most likely form an ionic compound with fluorine (F). Sodium readily gives up an electron to fluorine to achieve a stable electron configuration, forming sodium fluoride (NaF) which is an ionic compound.
The most likely charge on an ion formed by an element with a valence electron configuration of ns1 is +1. This is because elements with ns1 configuration tend to lose one electron to achieve a stable noble gas configuration, which results in a +1 charge.
A filled highest occupied principal energy level