None of the materials listed is a heavy metal, because most of them are compounds, and only elements are ever heavy metals. The only one on the list that does not contain a heavy metal is chlorine, which is a nonmetallic element.
If the sodium sulfate and barium nitrate are both in solution in water, a precipitate of barium sulfate will be formed, because this salt is much less soluble in water than barium nitrate, sodium sulfate, or sodium nitrate.
With x being lead nitrate, and b copper sulfate. a=atoms, and c=carbon.
Ammonium sulfate reacts with barium nitrate to form ammonium nitrate and barium sulfate. (NH4)2SO4 + Ba(NO3)2 ==> 2NH4NO3 + BaSO4 It is a double replacement reaction. that is the correct answer
When copper (II) sulfate and lead nitrate are mixed together, they will undergo a double replacement reaction. The copper will exchange places with the lead, forming copper (II) nitrate and lead sulfate as the products. The balanced chemical equation for this reaction is: CuSO4 + Pb(NO3)2 -> Cu(NO3)2 + PbSO4.
When aqueous calcium nitrate is added to aqueous lithium sulfate, a double displacement reaction occurs. The calcium and lithium ions switch places to form calcium sulfate and lithium nitrate. This reaction results in the formation of two new compounds: CaSO4 and LiNO3.
No reaction will occur between Potassium Sulfate and Ammonium Nitrate.
When lead(II) nitrate and sodium sulfate react, lead(II) sulfate and sodium nitrate are formed through a double displacement reaction. The balanced chemical equation for this reaction is: Pb(NO3)2 + Na2SO4 → PbSO4 + 2NaNO3. Lead(II) sulfate is a precipitate that appears as a white solid when this reaction occurs.
Combining sodium sulfate and barium nitrate would result in the formation of barium sulfate and sodium nitrate. Barium sulfate is a white precipitate that is insoluble in water, while sodium nitrate remains in solution.
If the sodium sulfate and barium nitrate are both in solution in water, a precipitate of barium sulfate will be formed, because this salt is much less soluble in water than barium nitrate, sodium sulfate, or sodium nitrate.
To determine the number of grams of lithium nitrate needed to make 250 grams of lithium sulfate, you need to calculate the molar mass of lithium sulfate and lithium nitrate, then use stoichiometry to find the ratio of lithium nitrate to lithium sulfate. Finally, apply this ratio to find the mass of lithium nitrate needed for the reaction. Lead sulfate is not involved in this calculation as it is not part of the reaction between lithium nitrate and lithium sulfate.
The chemical reaction between lead nitrate (Pb(NO3)2) and potassium sulfate (K2SO4) produces solid lead sulfate (PbSO4) and potassium nitrate (KNO3) in solution. The balanced chemical equation is: Pb(NO3)2 + K2SO4 -> PbSO4(s) + 2KNO3.
Hydrated sodium, sulfate, silver, and nitrate ions. (The ions already exist in the sodium sulfate and silver nitrate solids, but may not be hydrated there.) since silver sulfate is not very soluble in water, most of the silver and sulfate ions will be removed from the water as solid precipitate, but some hydrated ions will remain in solution.
With x being lead nitrate, and b copper sulfate. a=atoms, and c=carbon.
When aluminum sulfate reacts with silver nitrate, aluminum nitrate and silver sulfate are formed. This is because the aluminum ions in aluminum sulfate replace the silver ions in silver nitrate due to the reactivity of the metals.
When barium nitrate and sodium sulfate mix, they form barium sulfate and sodium nitrate. Barium sulfate is a white solid that precipitates out of the solution, while sodium nitrate remains dissolved. This reaction can be used in chemistry labs to demonstrate precipitation reactions.
The spectator ions in the reaction between silver sulfate and barium nitrate are nitrate (NO3-) ions and sulfate (SO4^2-) ions. These ions do not participate in the formation of the precipitate (barium sulfate) and remain unchanged throughout the reaction.
When copper (II) sulfate reacts with silver nitrate, a white precipitate of silver sulfate is formed. Copper (II) ions from copper (II) sulfate react with nitrate ions from silver nitrate to form a soluble salt.