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298K and 1.0ATM is room temperature at sea level therefore any oxides that you might see in daily life would be present at this point. One of the most obvious would be Iron Oxide aka rust.

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Q: Which oxides exist as a gas at 298 K and 1.0 ATM?
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A 150.0 ML sample of gas is collected at 1.20 ATM and 25 C what volume does the gas have at 1.50 ATM and 20.0 Ccould you show work?

PV/T=PV/T 1.20 ATM * 150.0 ML / 25 C = 1.50 ATM * V / 20.0 C 1.20 ATM * 150.0 ML / 298 K = 1.50 ATM * V / 293.2 K 1.20 ATM * 150.0 ML / 298 K / 1.50 ATM * 293.2 K = V 118 ML = V


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0.783 g of hydrogen gas is placed in an container of volume 657 mL at a temperature of 342 K. What is the pressure in atm?


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P1= 1.26 ATMV1= 7.60 LV2= 2.93 LP2= ?P1V1= P2V2.. . P2= 1.26 x 7.60 /2.93= 3.27 ATM


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You must use the perfect gas law, which states that PV=nRTP= pressureV= volumen= number of molesR= universal gas constantT= temperaturerearranging the equation to solve for n we get n= PV/RTso n= 1.8(28.5)/8.314(298)n= 51.3/2477.572n= 0.021.09


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While STP is at 25oC (298 K) and 1 ATM, the ideal gas law (P1.V1 / T1 = P2.V2 / T2) states the following solution: [T2/T1]*[P1/P2]*V1 = V2[(273+25.0) K / (273+20.0) K] * [3.00 atm / 1.00 atm] * 720.0 mL =[298.0 / 293.0] * [3.00] * 720.0 = 2197 mL


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