Iodine. Add up all the superscript numbers to get 53, which is iodine's atomic number. Or, just look at the last term, 5p5. That's the element in period 5 that's one short of noble gas configuration.
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p5 or [Ar] 4s2 3d10 4p5
[Kr] 4d10 5s2 5p2
Xe, Ba2+
Technetium. The 4s2 is supposed to be written before the 3d10 and the 5s2 is supposed to be written before the 4d5.
1s2, 2s2, 2p6, 3s2 , 3p6, 4s2 , 3d10, 4p6, 5s2, 4d10, 5p6
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p1 is the electron configuration for Indium.
1s2 ,2s2 ,2p6 ,3s2 ,3p6 ,4d10 ,4s2. hope this will b helpful for some one
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p1 is the electron configuration for Indium.
It is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6.
It is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5.
The unabbreviated electron configuration of iodine is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5.
The unabbreviated electron configuration for iodine is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5.
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6
Pd, or palladium, is the group 10, period 5 transition metal. Thus, its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10. The shorthand version of this is [Kr] 4d10, since krypton's electron configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6.
The element, indium, is in group 13, period 5 of the periodic table. Thus its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 5s2 4d10 5p1. This can also be written as [Kr] 4d10 5s2 5p1 since krypton's electron configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 5s2.
The mistake in this electron configuration is in the 5p subshell, where it shows 5p5 instead of 5p6. The correct element for this configuration is Xenon (Xe). The correct electron configuration for Xenon is [Kr] 5s2 4d10 5p6.