the simple answer is itshouldn't be the iodine produced should give rise to a light purple to begin with provide it is dissolve in water, if in an inorganic solvent it may well be dependant on the solvent.
however my guess is the potassium iodine is dissolved in water and than has become contaminated with something like lead giving rise to lead iodide (yellow solid that participates out if memory serves this being the case you will have a gas given off at the negative electrode (anode) this will be hydrogen and a mix of purple and yellow solid at the positive electrode (cathode)
Literally, the correct formula for potassium and iodine at standard temperature and pressure would be " K and I2". The formula for the compound formed between potassium and iodine, however, is KI.
From the balanced chemical equation, 2 moles of potassium iodide (KI) react with 1 mole of fluorine (F2) to produce 2 moles of iodine (I2). Therefore, when 0.72 mol of fluorine reacts, it produces 0.72 mol/2 = 0.36 mol of iodine. To convert this to grams, you would multiply the moles by the molar mass of iodine (I2), which is approximately 253.8 g/mol. So, 0.36 mol * 253.8 g/mol ≈ 91.4 grams of iodine are produced.
To prepare iodine solution, dissolve iodine crystals in a mixture of water and potassium iodide (KI). The ratio of iodine to KI will determine the concentration of the solution. The solution should be stored in a dark bottle to prevent degradation from light exposure.
KI would be potassium iodine, but you asked KL, and there is no L element.
this is because iodine is not soluble in water and it is soluble in potassiuim iodide. so KI is used as a solvent, and the resulting potassium iodate is soluble in watre so we can determine iodine in the ticture.
The substance produced in the reaction of chlorine water and KI is potassium iodide (KI), which reacts with chlorine to form iodine. The confirmation of iodine's presence was done by its reaction with starch, producing a blue-black complex.
Electrolysis of KI (potassium iodide) results in the production of potassium ions (K+) and iodine gas (I2). At the anode, iodide ions lose electrons and form iodine gas, while at the cathode, potassium ions gain electrons and form potassium metal. Overall, the electrolysis of KI leads to the separation of its components into their constituent elements.
The KI NaOCl mixture will turn yellow upon the addition of NaOCl due to the oxidation of iodide ions to iodine.
The chemical formula for potassium iodine is KI
Iodine is in: Iodomethane (CH3I) that is produced by the marine environment, by microbial activity in rice paddies and in Potassium iodide (KI) a very soluble salt.
Literally, the correct formula for potassium and iodine at standard temperature and pressure would be " K and I2". The formula for the compound formed between potassium and iodine, however, is KI.
Potassium iodide (KI) is added in coulometry titration to help facilitate the generation of iodine (I2) following the reduction of iodate ions (IO3-) in the sample solution. The produced iodine can then be titrated with a standardized thiosulfate solution to determine the amount of substance being analyzed. Additionally, KI acts as a stabilizer for iodine, preventing its premature reaction or volatilization.
The compound KI consists of two elements, potassium (K) and iodine (I). Potassium is a metal, and iodine is a nonmetal.
KI
See: http://www.elmhurst.edu/~chm/vchembook/548starchiodine.html For demonstrating starch the concentrations are not essential. Dissolve so much I2 in a KI solution until you get a yellow-brownish colour.
From the balanced chemical equation, 2 moles of potassium iodide (KI) react with 1 mole of fluorine (F2) to produce 2 moles of iodine (I2). Therefore, when 0.72 mol of fluorine reacts, it produces 0.72 mol/2 = 0.36 mol of iodine. To convert this to grams, you would multiply the moles by the molar mass of iodine (I2), which is approximately 253.8 g/mol. So, 0.36 mol * 253.8 g/mol ≈ 91.4 grams of iodine are produced.
To prepare iodine solution, dissolve iodine crystals in a mixture of water and potassium iodide (KI). The ratio of iodine to KI will determine the concentration of the solution. The solution should be stored in a dark bottle to prevent degradation from light exposure.