Lattice energy increases with greater charge and smaller size.
Since the charges are the same for both compounds, you have to look at the sizes of the atoms, K and Na, and since both have Cl, you don't have to compare that with anything. K is larger than Na, so since NaCl has a smaller size and the same charge, it has higher lattice energy.
MgO > BeO > LiCl > Na2O > Na2S. Lattice energy is directly proportional to the charges of the ions and inversely proportional to the size of the ions. MgO has the highest lattice energy due to the strong attraction between the highly charged ions, while Na2S has the lowest due to lower charges and larger ions.
Methane (CH4) will not have ionic bonds. It is a covalently bonded compound where electrons are shared between atoms, unlike in ionic compounds where electrons are transferred.
The ionic bonding causes the solubility. As the electronegative difference becomes more, the ions are easily soluble. K has more electronegativity than Na. Hence KCl is more soluble than NaCl in water
KBr + H2O = Kaq+ Braq- Haq+ OHaq-
Potassium bromide is composed of two elements: potassium (K) and bromine (Br). Potassium is a metal and bromine is a non-metal. The chemical formula for potassium bromide is KBr.
NaCl, NaOH, NaBr, KBr, KOH
KBr is used mostly in IR Spectroscopy techniques because it do not absorbs moisture at room temperature as compared to NaCl. More over it do not give its own peak.
KBr is used mostly in IR Spectroscopy techniques because it do not absorbs moisture at room temperature as compared to NaCl. More over it do not give its own peak.
MgO > BeO > LiCl > Na2O > Na2S. Lattice energy is directly proportional to the charges of the ions and inversely proportional to the size of the ions. MgO has the highest lattice energy due to the strong attraction between the highly charged ions, while Na2S has the lowest due to lower charges and larger ions.
KBr, or potassium bromide, is a solid at room temperature due to its ionic bonding and strong electrostatic forces between the potassium ions (K⁺) and bromide ions (Br⁻). These strong attractions create a crystalline lattice structure, which stabilizes the compound and requires significant energy to break apart. Additionally, the high melting point of ionic compounds like KBr contributes to its solid state under typical room temperature conditions.
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Methane (CH4) will not have ionic bonds. It is a covalently bonded compound where electrons are shared between atoms, unlike in ionic compounds where electrons are transferred.
Its neither, it's a salt!
In ionic compounds like KBr, CaS, LiF, BaO, and NaCl, the number of electrons transferred between the cation and anion corresponds to the charges of the ions. For KBr, NaCl, and LiF, one electron is transferred (K⁺/Br⁻, Na⁺/Cl⁻, Li⁺/F⁻). In CaS, two electrons are transferred (Ca²⁺/S²⁻), and in BaO, two electrons are also transferred (Ba²⁺/O²⁻). Thus, the number of electrons transferred varies based on the ionic charges of the respective compounds.
To prepare a 0.01N KBr solution, dissolve 0.74g of KBr in 1 liter of water. This will give you a solution with a molarity of 0.01N for KBr.
Potassium bromide (KBr) is commonly used in infrared (IR) spectroscopy as a method to prepare solid samples for analysis. The sample is mixed with KBr and compressed into a pellet, which allows for better handling and analysis. KBr has a wide transmission range in the IR spectrum and is transparent to infrared radiation, making it a suitable medium for the sample to be measured.
When you flame test the two solutions, any Na solution burns yellow, while any K solution burns violet/purple. So both the KCl and the KBr will burn purple, while both NaBr and NaCl will burn yellow.