K2CrO7 + H2C2O4 ------> K[Cr(C2O4)2(OH2)2] + H2O + CO2 the product which is formed is also known as trans isomer of potassium dioxalato diaquachroamte(III)
You would get calcium chloride... 2HCl + Ca(OH)2 = CaCl2 + 2H2O
CaCl2
Mercury (I) Hydroxide Hg OH2 (2 is subscript) Mercury(II) Hydroxide Hg (OH)2
Water is the oxyde of hydrogen - H2O.Added:I agree, though if 'seen' from the oxygen side it could be named as an hydride of Oxygen: OH2, (compare PH3, phosphorhydride) but it is rather unusual.
It is already balanced
NI3 does not exist. If NH3 is meant then the answer is: yes it has a dipole moment (like OH2, or better H2O)
I just worked this problem and I believe the answer is.. Fe(OH2) -> FeO + H2O
It's two hydrogen atoms bonded to an oxygen atom. IOW, water. Though it is not an atom, it is a molecule, more often written as H2O
oh2 ----> h2o
O = one Oxygen atom, H2 = two Hydrogen atoms. The symbol is more often written the other way round as "H2O" and it is the chemical formula for the compound known as "water".
6566
K2CrO7 + H2C2O4 ------> K[Cr(C2O4)2(OH2)2] + H2O + CO2 the product which is formed is also known as trans isomer of potassium dioxalato diaquachroamte(III)
Copper Hydroxide
CuSO4 * 5H2O ----> CuSO4 + 5H2O. This is true because CuSO4 * 5 H2O is a salt weakly bounded to water, that is why it is hydrous. When it decomposes, the weak bonds are broken making the products above. CuSO4*5H2O formula is [Cu(OH2)4]SO4*H2O CuSO4 + 5H2O --> [Cu(OH2)4]SO4*H2O
You would get calcium chloride... 2HCl + Ca(OH)2 = CaCl2 + 2H2O
as an antacid or a laxative