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aluminum bromide = AlBr3

the reason why there is 3 Br atoms is that aluminum is in group 3

chlorine gas exists as a diatomic Cl2 molecule

AlBr3 + Cl2 <------> AlCl3 + Br2

this type of reaction is a subsitiution reaction where chlorine and bromine ate both group 7 gas's and are interchangable

to balance this you'll notice that we lose 2 Br atoms, but have 3 at the start. This can look a bit confusing, so we need a number that both 3 and 2 go into to balance the Br atoms

These both go into 6 so if we use 2AlBr3 that gives us 6 Br on the left hand side and if we generate 3 Br2 on the right hand side we have the bromines balanced

now we've balanced the bromines, you noticed that we unbalanced the Al, so, to balance them again we need to form 2 AlCl3 on the right hand side and the Al is balanced

finally, by balancing the Al we unbalanced the Cl

there are 6 Cl on the right hand side but only 2 on the left hand side, so if we use 3 Cl2 on the left hand side then we have balanced the Cl's

your complete equation looks like this;

2AlBr3 + 3Cl2 <------> 2AlCl3 + 3Br2

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What is the chemical formula of an ionic compound of aluminum and chlorine be?

The chemical formula for the ionic compound formed between aluminum and chlorine is AlCl3. This is because aluminum typically forms a 3+ cation (Al^3+) and chlorine forms a 1- anion (Cl^-), requiring three chlorine atoms to balance the charge of one aluminum atom.


What is the maximum mass of aluminum chloride that can be formed when reacting 15.0 g of aluminum with 20.0 g of chlorine?

The balanced chemical equation for the reaction between aluminum and chlorine to form aluminum chloride is 2Al + 3Cl2 → 2AlCl3. Using the molar masses of aluminum and chlorine, we find that 15.0 g of aluminum is equivalent to 0.56 mol and 20.0 g of chlorine is equivalent to 0.28 mol. Since aluminum and chlorine react in a 2:3 ratio, 0.56 mol of aluminum would require 0.84 mol of chlorine. Therefore, the limiting reactant is chlorine, and the maximum mass of aluminum chloride that can be formed is 59.6 g.


What is the ratio of Aluminum atoms to Chlorine atoms in a molecule of Aluminum Chloride?

AlCl3 1 Aluminium to 3 Chlorine atoms 1:3


When 4 moles of aluminum are allowed to react with an excess of chlorine gas Cl2 how many moles of aluminum chloride are produced?

When 4 moles of aluminum react with an excess of chlorine gas, 4 moles of aluminum chloride are produced. This is because the balanced chemical equation for the reaction is: 2Al + 3Cl2 -&gt; 2AlCl3 This means that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride, so 4 moles of aluminum will produce 4 moles of aluminum chloride.


Aluminum bromide plus chlorine yield aluminum chloride and bromine?

The chemical equation for this reaction is: 2 AlBr3 + 3 Cl2 -&gt; 2 AlCl3 + 3 Br2 It is a redox reaction where aluminum bromide is oxidized to aluminum chloride and chlorine is reduced to bromine.

Related Questions

What is the chemical name for aluminum and chlorine?

The chemical name for aluminum is aluminum (Al) and for chlorine is chlorine (Cl). When these two elements combine, they form aluminum chloride, which has the chemical formula AlCl3.


Chemical equation for aluminum bromide plus chlorine yield aluminum chloride plus bromine?

Aluminum bromide (AlBr3) + Chlorine (Cl2) → Aluminum chloride (AlCl3) + Bromine (Br2)


What are the elements in aluminum chloride?

Aluminum chloride is a compound composed of aluminum and chlorine atoms. Its chemical formula is AlCl3, indicating that each molecule contains one aluminum atom and three chlorine atoms joined together.


Is aluminum chloride a salt?

Yes. Aluminum chloride is a chemical salt.


How many atoms of chlorine are in aluminum chloride?

There are 3 atoms of chlorine in aluminum chloride (AlCl3).


What happens when aluminum and chlorine combine?

When aluminum and chlorine combine, they form aluminum chloride (AlCl3), a white crystalline compound. This reaction is highly exothermic (produces a lot of heat) and can be violent. Aluminum chloride is commonly used as a catalyst in various chemical reactions.


What is the chemical formula of an ionic compound of aluminum and chlorine be?

The chemical formula for the ionic compound formed between aluminum and chlorine is AlCl3. This is because aluminum typically forms a 3+ cation (Al^3+) and chlorine forms a 1- anion (Cl^-), requiring three chlorine atoms to balance the charge of one aluminum atom.


A compound contains one aluminum atom for every three chlorine atoms?

The compound is aluminum chloride, with the chemical formula AlCl3. It is formed when aluminum reacts with chlorine to create a 1:3 ratio of aluminum atoms to chlorine atoms.


How is chemical formula aluminium chloride is form?

the chemical formula fro Aluminum chloride is AlCl3 this is because the charge of aluminum is +3 and for chlorine it's 1 so when ur making the chemical formula u switch the two charges and it becomes Al1Cl3 and in chemistry u don't have to put the 1 so u eliminate it and the answer becomes AlCl3


What is the maximum mass of aluminum chloride that can be formed when reacting 15.0 g of aluminum with 20.0 g of chlorine?

The balanced chemical equation for the reaction between aluminum and chlorine to form aluminum chloride is 2Al + 3Cl2 → 2AlCl3. Using the molar masses of aluminum and chlorine, we find that 15.0 g of aluminum is equivalent to 0.56 mol and 20.0 g of chlorine is equivalent to 0.28 mol. Since aluminum and chlorine react in a 2:3 ratio, 0.56 mol of aluminum would require 0.84 mol of chlorine. Therefore, the limiting reactant is chlorine, and the maximum mass of aluminum chloride that can be formed is 59.6 g.


How many atoms are there in aluminum chloride?

Aluminum chloride has the chemical formula AlCl3. This means one aluminum atom is bonded to three chlorine atoms. Therefore, in one molecule of aluminum chloride, there are a total of 4 atoms (1 aluminum atom + 3 chlorine atoms).


What is aluminum bromide plus chlorine yields aluminum chloride and bromine?

The chemical equation is:2 AlBr3 + 3 Cl2 = 2 AlCl3 + 3 Br2