3q+11+8q>99
3q+11+8q>99
It is not an equation if it does not have an equals sign. You could simplify it but not solve it.
(3)(q-11) = 3q-33
9q2 is the square of 3q - so 3q is the result of dividing 9q2 by 3q.
q=-6
(p-3q) (p-3q) =p2+3pq+3pq+9q2 =p2+6pq+9a2 this is answer hehehhe (jhaylotte)
steps to solve 4(3q-q): =(4)(3q+-q) =(4)(3q)+(4)(-q) =12q-4 answer: 8q
P = 3a - 3q Add 3q to each side: P + 3q = 3a Double each side: 6a = 2P + 6q
3q = 18 q = 6
3q + 2z, although it could be 2*(3q+z)
(4p - 1)(3q - 2)
3q + 11 + 8q > 99 11q + 11 > 99 Subtract '11' from both sides 11q > 99 - 11 11q > 88 Divide both sides by (+)11 q > 88/11 q > 8 ('q' is greater than '8'). Verification When q = 7 (8) 11(9) = 99 > 88 (True) 1