sounds like a pentagon.
* * * * *
A very poorly worded question so much of the answer is based on trying to guess what the question is about.
It cannot be a 2-dimensional object since a square face is mentioned in the question. It cannot be a "normal" 3-dimensional polyhedron because with 5 vertices and 5 edges, the Euler characteristic would mean it had only 2 faces!
1 face, 4 edges and 4 vertices.
Vertices are the corners of the polygon so there are 4 in this instance and there are also 4 edges to a square which defines the 1 face.
A sphere has no edges or edges but its face is globular.
A pyramid with an n-sided base will have n + 1 vertices, n + 1 faces, and 2n edges. 5 faces, 5 vertices, 8 edges
A square pyramid.
3 vertices, 3 edges and 1 face.
0 edges, 1 face and 0 vertices.
1 face, 1 edges & 0 vertices
A square based pyramid.
A trapezium has 1 face, 4 edges and 4 vertices.
Faces = 5 Edges = 8 Vertices = 1
The shape can't exist: if you imagine a square face in 2D you have 4 edges and 4 vertices. Adding a further vertex out of the plane (introducing a 3rd dimension) you MUST have 4 more edges to join the original 4 vertices to the novel vertex. This sums to 8 edges as a minimum.This is of course assuming Euclidean geometry.