Pressure is given by the formula -pgh , where p= desity of water , g gravity ,and h height .
So pressure at the depth 3.5m =1*9.8*3.5 pa
=34.3 pa.
(Assuming density of water to be 1).
approximately 0.8 bar
The pressure at any point at the bottom of the tank is determined by the height of the water column above that point. The pressure is given by the formula P = ρgh, where ρ is the density of water (around 1000 kg/m^3), g is the acceleration due to gravity (around 9.81 m/s^2), and h is the height of the water column (3.5 meters in this case). Plugging in these values will give you the pressure at the bottom of the tank.
The pressure at the bottom of the tank can be calculated using the formula P = ρgh, where ρ is the density of water (1000 kg/m³), g is the acceleration due to gravity (9.81 m/s²), and h is the height of the water column (4 meters). Plugging in these values, we get P = 1000 * 9.81 * 4 = 39240 Pa, or 39.24 kPa.
c-34.3kpa
Since we are ignoring atmospheric pressure, the pressure at the bottom of the tank is given by p = dgh. Where d equals density, g is acceleration of gravity, and h is the height below the fluid surface. In this case, the density of water is 10^3 kg/m^3, the acceleration of gravity is 9.8 m/s^2, and the height is 4 m. This means the pressure is 39.2 kPa.
Pressure is given by the formula P = h * d * g Here h is the depth or height of surface right from bottom. Given as 3.5 m d = density of water i.e. 1000 kg/m^3 g = 9.8 m/s^2 You could plug and get the value of P at bottom in pascal
P=pgh, remeber that g=9.8 , so ignoring the atmosheric pressure you would just multiply 9.8x4 and you would get 39.2KPa ... i'm not that good with physics so just analyze what is given to you and figure out if the answer is correct or not. Hope I helped :)
Ignoring atmospheric pressure, overall pressure is equivalent to the specific weight of the liquid times the depth. Water has a density of 1 kg/m3 and gravity has a force of 9.81 m/s2. So specific weight = density * gravity = 9.81 kg/m2s2. When multiplied by 4 meters, the answer is 39.24 Pascal's. (1 Pascal = 1kg/ms2).
Thank you. You're very kind. Each square centimeter of the flat bottom has (1 x 400) = 400 cubic centimeters of water standing over it. The mass of 400 cm3 of water is 400 grams = 0.4 kilogram. Its weight is 3.92 newtons, or about 0.88 pounds. The pressure is -- 3.92 newtons per square centimeter -- 0.88 pounds per square centimeter -- 5.69 pounds per square inch (all rounded)
The pressure at any point at the bottom of the tank is determined by the weight of the water above that point. It is given by the formula P = ρgh, where P is the pressure, ρ is the density of water, g is the acceleration due to gravity, and h is the height of the water column. So, the pressure at the bottom of the tank would be ρgh = (1000 kg/m^3)(9.81 m/s^2)(4 m) = 39,240 Pa.
1.5
It depends on whether the pipe is open or closed and what it contains. If the pipe is full of water to a height of 40 m and open at the top, the pressure at the bottom is about 57 psig. The diameter doesn't matter.