-7
9 - x2 will factor into (3 - x)(3 + x)
x2 + 9 = (x + 3i)(x - 3i) The answer is based on a knowledge of imaginary and complex numbers where i2 = -1
x2-9x = x(x-9)
(x2 - 3)(x2 + 3)(x4 + 9)
x2 + 10x + 25 --> (x + 5)2
Factor x4 - 81. Step 1: both numbers have square roots and have a minus sign between them so the first factor result is (x2+9)(x2-9). Step 2: (x2+9) does not factor, but (x2-9) factors to (x+3)(x-3). Step 3: Solution is (x2+9)(x+3)(x-3).
If you mean "factors", the two monomials have the common factor x2. Divide each factor by x2 to get the other factor.
x2-6x+9 = (x-3)(x-3) when factorised.
9 - x2 = 32 - x2 = (3 - x)(3 + x)
(x - 9)(x + 1)
x -9
(x + 3)(x - 3)