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How do you calculate the pressure on the base of a circular water tank of 3m2 base area and 2.5m deep if it was filled with water?
Pressure is equal to force divided by area (F/A). You already know that the area is 3m2, so now you just have to find out the force of the water on the base of the tank. First of all, you need to work out how much water there is, so you can determine it's mass and from this how heavy it is in the tank (this is the force - the waters own weight).
The volume of the water tank is Area times height (V = A * h). So the volume of this water tank is 3*2 = 6m3. Now, every m3 of water has a mass of 1 kg, so in this tank we have 6 * 1kg = 6kg of water. The weihgt of the water (force towards ground) is its mass times the acceleration due to gravity (what's holding your feet to the ground), as given by Newton's second law. So the water's weight (or force on the bottom of the tank) is 6 * 9.8 (acceleration due to gravity = 9.8 ms2) = 58.8 Newtons.
And now we work out pressure... Pressure = force/area = 58.8 N/3m2 = 19.6 N/m2
Hope that helps
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