1 - ūnus
2 - duo
3 - trēs
4 - quattuor
5 - quīnque
6 - sex
7 - septem
8 - octō
9 - novem
10 - decem
11 - ūndecim
12 - duodecim
13 - trēdecim
14 - quattuordecim
15 - quīndecim
16 - sēdecim
17 - septendecim
18 - duodēvīgintī
19 - ūndēvīgintī
20 - vīgintī
2
The answer is 20C10 which is 20!/[10!(20-10)!] = 184756
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
There is not such thing as Latin numbers. The questioner probably means to say Roman numerals. To write 161 in Roman numerals, one should use C for 100, L for 50, X for 10, and I for 1. All together, it is CLXI.
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90
Unus, duo, tres, quattuor, quinque, sex, septem, octo, novem, decem is 1-10 in Latin
11
145
There are 180. 10 through 99 and -10 to -99.
Exactly 3,628,800, or 10!.
They are: 4 6 8 9 and 10