1 - ūnus
2 - duo
3 - trēs
4 - quattuor
5 - quīnque
6 - sex
7 - septem
8 - octō
9 - novem
10 - decem
11 - ūndecim
12 - duodecim
13 - trēdecim
14 - quattuordecim
15 - quīndecim
16 - sēdecim
17 - septendecim
18 - duodēvīgintī
19 - ūndēvīgintī
20 - vīgintī
2
The answer is 20C10 which is 20!/[10!(20-10)!] = 184756
There is not such thing as Latin numbers. The questioner probably means to say Roman numerals. To write 161 in Roman numerals, one should use C for 100, L for 50, X for 10, and I for 1. All together, it is CLXI.
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
Unus, duo, tres, quattuor, quinque, sex, septem, octo, novem, decem is 1-10 in Latin
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90
11
There are 180. 10 through 99 and -10 to -99.
145
They are: 4 6 8 9 and 10
Exactly 3,628,800, or 10!.