abcd
535. (2140/4 = 535)
42
To determine how many ways 4 students can be chosen from a class of 12 and assigned different tasks, we first select 4 students from the 12, which can be done in ( \binom{12}{4} ) ways. Then, we can assign the 4 different tasks to these students in ( 4! ) (24) ways. Therefore, the total number of ways to choose the students and assign the tasks is ( \binom{12}{4} \times 4! = 495 \times 24 = 11,880 ).
the answer would be 4 students
3
4/9 x 18 = 8 so there are 8 grils
To determine how many ways an adviser can choose 4 students from a class of 12, we use the combination formula, which is given by ( C(n, r) = \frac{n!}{r!(n-r)!} ). Here, ( n = 12 ) and ( r = 4 ). Thus, the calculation is ( C(12, 4) = \frac{12!}{4!(12-4)!} = \frac{12!}{4!8!} = 495 ). Therefore, there are 495 ways for the adviser to choose 4 students from the class.
12
8 students out of 30 is (8 / 30) or (4 / 15)■
7 because we will divide 31 ÷4
333
33 yards at that rate.