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What else can I help you with?
An example of a boolean expression?
a ⊕ b = ab' + a'b
What is the equivalent expression to 11 plus ab?
11 + ab is the expression.
Use Boolean algebra to simplify the logic function and realize the given function and minimized function using discrete gates. f equals ab c plus abc plus ac plus bc plus abC.?
Do you mean F = abc + abc + ac + bc + abc' ? *x+x = x F = abc + ac + bc + abc' *Rearranging F = abc + abc' + ab + bc *Factoring out ab F = ab(c+c') + ab + bc *x+x' = 1 F = ab + ab + bc *x+x = x F = bc
What is the output of AB and AB?
The output of AB and AB is simply AB, as the logical AND operation between two identical inputs (AB) results in the same input. In Boolean algebra, if A and B are both true, then AB is true; otherwise, it is false. Therefore, the expression AB AND AB does not change the value of AB.
Write an algebraic phrase for this expression ab plus 2?
ab increased by 2
How do you simlify variable algebraic expression with exponent?
Here are some rules that can help you simplify such expressions, in some cases. (ab)c=abc abac = ab+c ab/ac = ab-c
How do you find the sum of -5ab plus 7ab plus -9ab plus ab plus -2ab?
-5ab + 7ab -9ab + ab -2ab ... Let's simplify that a bit:ab(-5+7-9+1-2) = -8ab
What is the answer to 2c plus ab 3d?
The expression "2c plus ab 3d" can be interpreted as (2c + ab + 3d). To provide a numerical answer, specific values for the variables (a), (b), (c), and (d) are needed. Without those values, the expression remains in its algebraic form.
Ab plus 3a plus b squared plus 3b?
This expression can be factored. ab + 3a + b2 + 3b = a(b + 3) + b(b + 3) = (a + b)(b + 3)
Factor this expression Check by multiplying factors xy-xyb-abx plus ab?
The expression, as given, cannot be factorised.
What does a2 plus ab equals h2 mean?
It is an expression and a term that are of equal value
What is the boolean expression for a 2 out of 3 OR gate?
If the inputs are ABC. The inputs required to give an output are ABC, AB, AC and BC. Using the Absorption law X + X.Y = X we can remove ABC, the inputs required are therefore AB, AC and BC.
