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The expression (3n + 1) represents a sequence where (n) is a positive integer. The first five terms can be found by substituting (n) with the values 1, 2, 3, 4, and 5. The first five terms are:
- For (n=1): (3(1) + 1 = 4)
- For (n=2): (3(2) + 1 = 7)
- For (n=3): (3(3) + 1 = 10)
- For (n=4): (3(4) + 1 = 13)
- For (n=5): (3(5) + 1 = 16)
Thus, the first five terms are 4, 7, 10, 13, and 16.
What else can I help you with?
What are the first five terms for 3n-2?
5
What makes 3n-1 a composite number?
Nothing. If n is 2, 3n - 1 is 5 and 5 is prime.
If the nth term is 3n - 7 What is 1 2 3 4 and 5?
The first, second, third, fourth, and fifth terms of 3n - 7 are as follows:1: -42: -13: 24: 55: 8
First 5 terms for 3n plus 4?
The first five positive integer terms for 3n + 4 are: 1 = 7 2 = 10 3 = 13 4 = 16 5 = 19
Solve for n 3n 2 5?
1/5
What is the first 5 terms of -3n?
8
How do you solve 3n - 5 equals 19?
3n -5 = 19 3n = 19+5 3n = 24 n = 8
What are the first 5 terms of 16 - 3n?
taking the 1st term as n=1 the 2nd term as n= 2 etc then the first 5 terms of 16-3n are : 1st : 16-3 = 13 2nd : 16-6 = 10 3rd : 16-9 = 7 4th: 16-12 = 4 5th : 16-15 = 1 hope this helps
Who do you work out the nth term for 11 23 41 65?
3n(n+1] + 5 is the nth term
What are the factors of 9n2-30n 25?
If that's +25, that factors to (3n - 5)(3n - 5) or (3n - 5)2
What are the first 5 terms in the sequence 3n-3?
To find the first 5 terms, plug 1, 2, 3, 4 and 5 in for n:3*1-3 = 03*2-3 = 33*3-3 = 63*4-3 = 93*5-3 = 12The first five terms are 0, 3, 6, 9 and 12.
What are the first five terms of the sequence 3n-3?
6
