0.35kg
1000 g = 1 kg so 35 g = 35/1000 = 0.035 kg. Simple!
It depends how much each of the strawberries weighed. You have 0.35 kg left, so if each strawberry was 35g, you would have ten of them left.
To determine the change in the freezing point of water when 35g of sucrose is dissolved in 300g of water, we can use the freezing point depression formula: ΔTf = i * Kf * m, where i is the van 't Hoff factor (1 for sucrose), Kf is the freezing point depression constant for water (1.86 °C kg/mol), and m is the molality of the solution. First, calculate the number of moles of sucrose: ( \text{moles} = \frac{35g}{342.3 g/mol} \approx 0.102 moles ). The mass of the solvent (water) in kg is 0.3 kg, so the molality ( m = \frac{0.102 moles}{0.3 kg} \approx 0.34 , mol/kg ). Thus, the change in freezing point is ( ΔTf = 1 * 1.86 °C kg/mol * 0.34 , mol/kg \approx 0.63 °C ). Therefore, the freezing point of the solution will decrease by approximately 0.63 °C.
volume of 35g
A common item that weighs around 35g is a large paper clip.
No.
30g - 35g
To calculate the volume, you can use the formula: Volume = Mass / Density. Given a mass of 35g and a density of 5g/cm³, the volume would be 35g / 5g/cm³ = 7 cm³. Therefore, the volume of the substance is 7 cm³.
It is 7*(6 + 5g)
That is approximately 2.3 tablespoons
That is 1/2 cup.
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