in single bond hybridization will be sp3 and take tetrahedral shape as in CH4 in double bond hybridization will be sp2 and take planar triangle shape as in C2H4
in triple bond hybridization will be sp and take linear shape as in C2H2
The hybridization of O2 is sp2. In O2, both oxygen atoms are connected via a double bond formed by overlap of two p orbitals and one sigma bond formed by overlap of two sp2 hybridized orbitals on each oxygen atom.
Two pi bonds are formed when sp2 hybridization occurs in ethene (C2H4). This is because each carbon atom forms a pi bond with the neighboring carbon atom, resulting in a double bond between the carbons.
it gave me two answer and that is it
Hybridization comes from very complicated Quantum Mechanics and says that as many molecular orbitals that are being combound, the exact same number of hybrid orbitals are formed. Essentially, spherical s-orbitals and somewhat ellipcitcal p-orbitals are fused to make new orbitals that are identical. Example: 4 equivalent (tetragonal) sp3-orbitals in CH4 molecules.
Double covalent bond: one sigma- and one pi-bond.
A covalent bond is formed. A molecular compound is formed.
A covalent bond is formed. A molecular compound is formed.
Yes, molecular compounds can be formed from semimetals. These compounds result from the bonding of semimetal atoms to form molecules, often through sharing electrons in covalent bonds. Examples of molecular compounds with semimetals include carbon monoxide (CO) and boron trifluoride (BF3).
wo. A strange question! if you hybridise the 3s and 3 p orbitals you end up with sp3 and still get the same answer. Perhaps the hybridisation involves d orbitals, if that is what you are being taught.
A macromolecule is formed from many molecules linked together in a chain and of course has a higher molecular mass.
Biological molecules were trapped in molecular bubbles. Cell like structures formed from molecular bubbles-apexx
In molecular BH3 the molecule is planar with bond angles of 120o so the hybridisation of the central boron atom is sp2. In the dimer B2H6 the molecule has two bridging hydrogens. The hybridisation of each boron is approxomately sp3 and each bridge has a 3 centre B-H-B bond formed by the overlap of the sp3 orbtals on the B atoms and the s orbital on the hydrogen.