The numbers 21 and 126 are divisible by seven. The numbers 88 and 255 have a remainder when divided, so they are not divisible by seven.
126 is divisible by 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, and 126.
126 is divisible by 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126.
Any element of the set of numbers of the form 126*k, where k is an integer, is evenly divisible.126*k = 9*(14*k)126*k = 6*(21*k)126*k = 7*(18*k)
No, it is divisible by: 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126
21*6=126
The least common multiple of the numbers 7, 21 and 18 is 126.
Some numbers that are divisible by 63 is 1,3,7,9, and 21.
Numbers that are divisible by both 6 and 7 must be divisible by the least common multiple of 6 and 7, which is 42. Therefore, the numbers divisible by both 6 and 7 are multiples of 42. This includes numbers like 42, 84, 126, and so on.
The factors that 252 is divisible by: 1, 2, 3, 4, 6, 7, 9, 12, 14, 18, 21, 28, 36, 42, 63, 84, 126, and 252.
Factor tree:126|63 and 2|21 and 32 x 3 x 21 = 126
They are members of the infinite set of numbers of the form 21*k where k is an integer.
1, 3, 7, 21