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What sum of two numbers is 8 and their difference is 12 Find the numbers?
Let X be one number and Y the other. So, X + Y = 8 and X - Y = 12 Solve the set of equations simultaneously or use substitution method. X + Y = 8 X - Y = 12 (ADD THIS EQUATION TO FIRST ONE) _______________ 2X = 20, So X =10 and solving for Y using either equation, Y = -2
If the sum of two numbers is 6 and there difference is -2 what are the two numbers?
Let numbers be x and y. Then, x + y = 6 x - y = -2 add up both equations 2x + y - y = 6 + (-2) 2x = 4 divide by 2 to both sides x = 2 Since the sum of the numbers is 6 and one of the numbers is 2, then the other number is 4 (6 - 2). Check: 2 + 4 = 6 2 - 4 = -2
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point 4 2?
The equation in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. Given the slope m = 2 and the point (4, 2), plug in these values to find the equation: 2 = 2(4) + b. Solve for b to get b = -6. Therefore, the equation of the line is y = 2x - 6.
The sum of a certain number and a second number is -42. The difference of the first number and the second number is 52. Find the number?
Let the first number be x, and the second number be y. So, x + y = -42 x - y = 52 add the equations; 2x = 10 divide by 2 both sides; x = 5 substitute 5 for x into the first equation; 5 + y = -42 subtract 5 to both sides; y = - 47 So the numbers are 5 and -47. Check: 5 + (-47) = -42 5 - (-47) = 5 + 47 = 52.
What is 2y-2x-8 3y-18-3x using elimination method?
To solve this system of equations using the elimination method, we need to eliminate one variable by adding or subtracting the two equations. By looking at the equations given (2y-2x-8 = 0 and 3y-18-3x = 0), we can choose to eliminate either the x or y variable. Let's choose to eliminate the x variable: Multiply the first equation by 3 and the second equation by 2 to make the coefficients of x the same: 6y - 6x - 24 = 0 6y - 36 - 6x = 0 Now we can subtract the second equation from the first equation to eliminate x: (6y - 6x - 24) - (6y - 36 - 6x) = 0 Simplify to get -12 = 0, which is a false statement. Therefore, the system of equations is inconsistent and has no solution.
What is the slope of 2x plus y equals 20?
2x + y = 20 y = -2x + 20 Slope = -2 m=-2
What are the intercepts of the equation 2x 5y 20?
2x+5y=20 Solve for y -2x -2x 5y=20-2x 5 5 5 y=4-2x 5
12x - 5y equals 30 and y equals 2x - 6 what is the y value?
12x - 5(2x - 6) = 30 12 x - 10x + 30 = 30 2x = 0, x = 0 y = -6
What is the x value of 12x - 5y equals 30 y equals 2x - 6?
Substitute 2x - 6 for y in first equation: 12x - 5(2x - 6) = 30 ie 12x - 10x + 30 = 30 so 2x = 0 making x = 0 and y = -6
Y 2x - 32?
-30
How do you find the equation of a line through 10 14 parallel to 1y equals -2x plus 4?
The slope will be the same but the y intercept will change:- y -14 = - 2(x - 10) y -14 = -2x +20 y = -2x +20 +14 y = -2x +34
What is the slope of 2x-6y equals 20?
2x-6y = 20 -6y = -2x+20 y = 1/3x-20/6 The slope is 1/3
What are the x and y intercepts of 2x plus 3y equals 30?
To find the x-intercept of the equation (2x + 3y = 30), set (y = 0): (2x = 30), giving (x = 15). For the y-intercept, set (x = 0): (3y = 30), resulting in (y = 10). Therefore, the x-intercept is (15) and the y-intercept is (10).
Enter the answer as an ordered pair 2y plus 2x equals 20 y - 2x equals 4?
2y + 2x = 20 y - 2x = 4 Add the two equations: 3y = 24 so that y = 8 Substitute this value of y in the second equation: 8 - 2x = 4 then 4 = 2x so that x = 2 Thus the ordered pair (y,x) = (8,2)
What is x in x square plus 2 times x?
(x^2)+2x=y? or X^(2+2x)=y either way whats the value of y? so we can determine x
How would 2x plus 5y plus 30 equals 0 be worked out?
2X+5Y+30=0 So you subtract 30 from each side. 2X+5Y+30-30=0-30. So you know 2X+5Y=-30. now there are many different possibilities for X and Y unless there is a specification. here are some possibilities=X=0,Y=6 or X=A5,Y=0 or X=5,Y=4
What is the slope of 2x - 7y 20?
If: 2x-7y = 20 Then: y = 2/7x -20/7 which is now in slope-intercept form
