It depend, what is x and y?
Let X be one number and Y the other. So, X + Y = 8 and X - Y = 12 Solve the set of equations simultaneously or use substitution method. X + Y = 8 X - Y = 12 (ADD THIS EQUATION TO FIRST ONE) _______________ 2X = 20, So X =10 and solving for Y using either equation, Y = -2
Let numbers be x and y. Then, x + y = 6 x - y = -2 add up both equations 2x + y - y = 6 + (-2) 2x = 4 divide by 2 to both sides x = 2 Since the sum of the numbers is 6 and one of the numbers is 2, then the other number is 4 (6 - 2). Check: 2 + 4 = 6 2 - 4 = -2
The equation in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. Given the slope m = 2 and the point (4, 2), plug in these values to find the equation: 2 = 2(4) + b. Solve for b to get b = -6. Therefore, the equation of the line is y = 2x - 6.
Let the first number be x, and the second number be y. So, x + y = -42 x - y = 52 add the equations; 2x = 10 divide by 2 both sides; x = 5 substitute 5 for x into the first equation; 5 + y = -42 subtract 5 to both sides; y = - 47 So the numbers are 5 and -47. Check: 5 + (-47) = -42 5 - (-47) = 5 + 47 = 52.
To solve this system of equations using the elimination method, we need to eliminate one variable by adding or subtracting the two equations. By looking at the equations given (2y-2x-8 = 0 and 3y-18-3x = 0), we can choose to eliminate either the x or y variable. Let's choose to eliminate the x variable: Multiply the first equation by 3 and the second equation by 2 to make the coefficients of x the same: 6y - 6x - 24 = 0 6y - 36 - 6x = 0 Now we can subtract the second equation from the first equation to eliminate x: (6y - 6x - 24) - (6y - 36 - 6x) = 0 Simplify to get -12 = 0, which is a false statement. Therefore, the system of equations is inconsistent and has no solution.
2x + y = 20 y = -2x + 20 Slope = -2 m=-2
2x+5y=20 Solve for y -2x -2x 5y=20-2x 5 5 5 y=4-2x 5
12x - 5(2x - 6) = 30 12 x - 10x + 30 = 30 2x = 0, x = 0 y = -6
Substitute 2x - 6 for y in first equation: 12x - 5(2x - 6) = 30 ie 12x - 10x + 30 = 30 so 2x = 0 making x = 0 and y = -6
-30
The slope will be the same but the y intercept will change:- y -14 = - 2(x - 10) y -14 = -2x +20 y = -2x +20 +14 y = -2x +34
2x-6y = 20 -6y = -2x+20 y = 1/3x-20/6 The slope is 1/3
To find the x-intercept of the equation (2x + 3y = 30), set (y = 0): (2x = 30), giving (x = 15). For the y-intercept, set (x = 0): (3y = 30), resulting in (y = 10). Therefore, the x-intercept is (15) and the y-intercept is (10).
2y + 2x = 20 y - 2x = 4 Add the two equations: 3y = 24 so that y = 8 Substitute this value of y in the second equation: 8 - 2x = 4 then 4 = 2x so that x = 2 Thus the ordered pair (y,x) = (8,2)
(x^2)+2x=y? or X^(2+2x)=y either way whats the value of y? so we can determine x
2X+5Y+30=0 So you subtract 30 from each side. 2X+5Y+30-30=0-30. So you know 2X+5Y=-30. now there are many different possibilities for X and Y unless there is a specification. here are some possibilities=X=0,Y=6 or X=A5,Y=0 or X=5,Y=4
If: 2x-7y = 20 Then: y = 2/7x -20/7 which is now in slope-intercept form