Hi I have just come accross this question and I don't know how old it is. I have some experience with batteries. If the battery is a standard lead acid battery then there is every possibility that he is correct. The ultimate answer will be supplied by the battery itself. Put it on charge and leave it there for a week or so and see what the result is. The problem with the battery will be that the sulphate on the plates has gone stale. There are devices available that have a good chance of saving the battery but they are designed for 12Volt batteries. They deliver high voltage spikes back into the battery and that helps to break up the sulphate on the plates, but there are no gaurantees. If you can get one of these devices you will have to apply it to the battery in 3 separate 12Volt groups. I hope this helps
Depends on the chemistry. A standard D cell has 1.5 VDC. Oxy Nickel Hydroxide and Lithium cells have a slightly higher voltage of 1.7 VDC NiCd or NiMH rechargeable then 1.2 VDC at full charge.
To put simply it is where the system is ballanced. Imagine a wave that's getting bigger and bigger as each cycle passes, this is known as an unstable system. Again imagine a wave getting smaller and smaller with each cycle, this is a stable system that tends to zero when this cycle meets the zero point the system is said to have reached its "steady-state" the time in which it takes to reach this state is usually a factor as well as the "overshoot" Imagine putting a current into a system "turning it on" say it requires 3volts so the zero point discussed before would be the 3Volt point. When you turn the system on it doesnt just reach 3Volts instantly the power could possibly run past 3Volts, known as overshoot, then start to oscillate until it settle down much like a spring. When the oscillations settle down the system has reached steady state. dampening is commonly used to achieve this and prevent overshoot. Jason MEng
To put simply it is where the system is ballanced. Imagine a wave that's getting bigger and bigger as each cycle passes, this is known as an unstable system. Again imagine a wave getting smaller and smaller with each cycle, this is a stable system that tends to zero when this cycle meets the zero point the system is said to have reached its "steady-state" the time in which it takes to reach this state is usually a factor as well as the "overshoot" Imagine putting a current into a system "turning it on" say it requires 3volts so the zero point discussed before would be the 3Volt point. When you turn the system on it doesnt just reach 3Volts instantly the power could possibly run past 3Volts, known as overshoot, then start to oscillate until it settle down much like a spring. When the oscillations settle down the system has reached steady state. dampening is commonly used to achieve this and prevent overshoot. Jason MEng
Use a simple step-down transformer. Using an iron rod, wind six turns of suitable wire around one end, and connect the ends to the 6V battery. At the other end of the rod, wind three turns, and connect the ends to the equipment. Secure the wires to the iron core with adhesive tape. The number of turns in the wire are irrelevant - so long as they're in the ratio of 2:1
Cube World cubes typically require LR44 button cell batteries to operate. These batteries are small, round, and commonly used in small electronic devices due to their compact size and long shelf life. It is important to replace the LR44 batteries when the cubes start to dim or malfunction to ensure optimal performance.
Assume you mean resistors in a series ckt, since in a parallel ckt the answer is 9V. First solve for total current: I=E/Rtotal Rt=10+20+30, or 9/60, so 150ma then for each R: E=IR R1=10, so 10*.15=1.5 R2=20, so 20*.15=3.0 R3=30, so 30*.15=4.5 The source 9V= the sum of the voltage drops as a sanity check.
The usual voltages produced by the power supply in a standard personal computer system are 5 volts and 12 volts.For more information see the Related Link shown below.
ANSWER:Imagine that all the elements of a simple circuit (such as a battery, a light globe , a switch, and a resistor ) When the switch is closed , the electric current flows round and round the circuit just the same way as water would flow through these elements if the circuit had a Water pressure supply and a thin section of pipe and then a thick section of pipe etc . The FLOW of the electricity in Amps can be thought of as the same thing as the Flow rate of water in a pipe system. The Ammeter, is put into the circuit between any 2elements of the circuit, so that the current flows through it , as well as all the other elements (parts) of the circuit. When current flows through the various elements the flow rate (Current) is the same in all of them. As the current flows through, there is a drop of pressure (Voltage) as the electrons flow through each of the elements of the circuit. The actual pressure(volts) in each piece of the circuit , can be measured, by placing a Voltmeter across any individual item in the circuit. The drop in pressure at each item is measured by connecting each terminal of a Voltmeter across the item you are dealing with. The voltage across the 2terminals of the supply will be perhaps 12 Volt(a car battery) The volts ' pressure ' across the globe may be say 8 volt and the volts across the switch may be 3volts and the volts across the resistor may be only 1 volt. Always think of Ampere, as 'Flow Rate', and think of Voltage as ' Electric Pressure' If a circuit has a spot where it splits into 2 separate circuits , and then turns back into 1 piece of circuit, the current flowing as it goes into the 2 different passages, is split up, or shared between the 2 passages, and then the 2 separate currents join together again as they re-enter the single part of the circuit. To find out the current flow in each of the 2 parallel parts of the circuit you must place the Ammeter in series within each of the 2peices of circuit . The 2 separate curent readings will have a total equal to the current reading in the main single passage circuit.