I = V/R
V= 20 volts
R = Total resistance = 10 * 0.5 = 10 ohms
I = 2 amps
The ammeter does affect the flow of current in a circuit, however, the resistance of the ammeter is so small in comparison to the circuit that the effect is negligible. It is connected in series.
Current will be decreased because of the resistance of the ammeter added to the circuit's resistance. In other words total resistance increases.
If the circuit is carrying current then that means that the load (resistance) is in the circuit. if an ohm meter is connected in the live circuit then there would be some voltage drop at the ohm meter but as the meter has very less resistance, this would damage the instrument.
4.8 ohms
an ideal ammeter has zero or negligible resistance when this is connected in series no effective resistance would be added in the circuit so that the value of curret that we get is exactly of the circuit only. but when the ammeter is connected in parllel as it has zero resistance , the resistor to which it is connected in parllel gets shorted and due to his the effective resistance of the circuit is changed and so the effective current ... due to this the w=value measured by the ammeter would be different (incresed due to dec. in effective resistance)
The ammeter does affect the flow of current in a circuit, however, the resistance of the ammeter is so small in comparison to the circuit that the effect is negligible. It is connected in series.
The resistance of the load is what causes an electric current to flow in a circuit.
The net resistance of the circuit connected to the battery in Figure 1 is the total resistance that the current encounters when flowing through the circuit. It is calculated by adding up the individual resistances of all the components in the circuit.
The current in a 220 volt circuit depends on the resistance of the load connected to it. Ohm's Law (I = V/R) states that current (I) is equal to voltage (V) divided by resistance (R). So, the current will vary based on the resistance of the circuit.
Current will be decreased because of the resistance of the ammeter added to the circuit's resistance. In other words total resistance increases.
:) It's connected together
When resistors are connected in parallel to the same voltage source, the overall resistance in the circuit decreases. This is because the current has multiple paths to flow through, reducing the total resistance that the current encounters.
If the circuit is carrying current then that means that the load (resistance) is in the circuit. if an ohm meter is connected in the live circuit then there would be some voltage drop at the ohm meter but as the meter has very less resistance, this would damage the instrument.
Because it is a metal so has lots of free electrons which when connected to a circuit detach from the atoms and move around the circuit. This produces a high current, so resistance will be low as current is high.
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
If the resistors are connected in series, the total resistance will be the sum of the resistances of each resistor, and the current flow will be the same thru all of them. if the resistors are connected in parallel, then the current thru each resistor would depend on the resistance of that resistor, the total resistance would be the inverse of the sum of the inverses of the resistance of each resistor. Total current would depend on the voltage and the total resistance
33 ohms