An iron ring of mean length 50cm has an air gap of 1mm and a winding of 200 turnsif the permeaility of iron is 300 when a current of 1 A flows through the coil find flux density?

Answer 1

Hi,

Known -

L=5 cm, N=200 turns, µr=300, µo=4π×10(-7)H/m, d=1mm=1×10(-3)m

A=πD²/4=7.85×10(-7)m²

Unknown -

flux density--->B=?

current--->I=?

Formulae -

Φ=BA; Φ=NI/R ;R=L/µA (reluctance);(Φ-magnetic flux);

By substitution-

BA=NI/R

B=µNI/L

B=µoµrNI/L= 1.501×I Tesla

substitute the numerical value of I to get the answer.

Regards

∞