The power dissipated by a circuit with a voltage of 12V and a current of 3A is 36W. Watts is Volts times Amps.
A final subcircuit is the circuit which the number of points supplied do not exceed 15A
Current is measured in a series circuit by the use of a multimeter. First, the power source must be attached to the circuit board. The board is attached to the multimeter, then that is attached back to the power source.AnswerCurrent is measured either with an ammeter, or with a multimeter set to measure current. The instrument must be connected in series with the other components in the circuit.
power supplied=sum of powers delivered to individual elements
if not disconnected you will measure the resistance of the circuit in parallel with the resistor.
The full circuit voltage
In both cases, the power dissipated is measured by multiplying the voltage across the circuit by the current through the circuit.
In both cases, the power dissipated is measured by multiplying the voltage across the circuit by the current through the circuit.
As far as circuit analysis is concerned, it means that power is being supplied rather than dissipated.
The voltage measured across an open in a series circuit is the equivalent of the sourse voltage.
The source of electrons in a circuit is supplied by an electric potential difference across two points . This potential difference in a circuit is called as voltage and is measured in joules per coulomb or volts.
The power dissipated by the complete circuit, no matter whether it's a series or parallel one, is the simple sum of the power dissipated by each component of the circuit.
Power dissipated by the entire series circuit = (voltage between its ends)2 / (sum of resistances of each component in the circuit). Power dissipated by one individual component in the series circuit = (current through the series circuit)2 x (resistance of the individual component).
The flow in a circuit is called the electric current and it is measured by voltages. The number of volts that are present in the charge will determine the strength of the electric current.
A final subcircuit is the circuit which the number of points supplied do not exceed 15A
A final subcircuit is the circuit which the number of points supplied do not exceed 15A
The energy dissipated.
Depends on the current. Put a resistor in-line with the current, then measure the voltage across the resistor. V=RI. So, divide the measured voltage by resistor value. Be careful with the size of the resistor, as Power dissipated in a resistor is R*I^2 or V^2/2. So, a 1-Amp current into a 1 Ohm resistor will result in a 1Watt power dissipated in the resistor. If it's too small, it'll burn. Also, notice that if you do that, you haven't measured the current in the original circuit. You've measured the current when an extra resistor is installed in the original circuit, and that's different.