0
Disadvantage of using diode as shunt element in clipper circuit?
Wiki User
∙ 9y ago
In shunt clippers, when the diode is in off condition, transmission of input signal must take place to output. But in the case of high frequency input signals, diode capacitance affects the operation of circuit adversely and the signal gets attenuated (which means that, it passes through diode capacitance to ground).
Wiki User
∙ 9y ago
Add your answer:
Earn +20 pts
How does the cut in voltage effects the output of a diode clipper?
For answering this question we have to consider the constant voltage drop model of the diode which says that if voltage across diode is less then its cut in voltage than assume diode to be open circuit and if it is greater then assume diode to be short circuit.Till the input voltage is less than the cut in voltage, diode is open circuit(thus no current through the circuit). Thus entire input voltage appears across the diode as output.When input voltage is greater than or equal to cut in voltage, then short circuit the diode. Thus, there will be no voltage drop across the diode as output.Thus cut in voltage decides when to consider the diode open circuit and when short circuit. It decides when the diode will have output when it will not.
What is clipper in electronic devices and circuit?
clipper is an AC application of diode. The Clipper clipps off a portion of the input signal waveform without distorting the remaining part of the alternating waveform. We can use different type of alternating waveforms as input such as sinusoidal, Triangular, square etc. There are different types of clippers e.g. series clipper, parallel clipper etc. but the method for solving all the type of circuits are same. So there is no need to remember the procedure for one particular clipper circuit. There are different types of clippers e.g. series clipper, parallel clipper etc. but the method for solving all the type of circuits are same. Now let us discuss the procedure with the help of a problem. Suppose we have given a clipper circuit shown below: Because clipper is an AC application of diode. So we apply an AC signal at the input Vi. Our aim is to find out the waveform of Vo. The solution steps are: Step 1 : First of all analyze the circuit by bifurcating the input waveform in positive half cycle and negative half cycle.Step 1.1 : Positive half cycle : Positive half cycle is equivalent to a battery of positive polarity and variable potential.Step 1.2 : Negative half cycle : Negative half cycle is equivalent to a battery of negative polarity and variable potential. Step 2 : Now analyze the circuit with positive half cycle.The next step is to check the condition of diode i.e., whether the diode is forward bias or reverse bias.In the circuit shown above it is clear that the diode is forward bias and hence equivalent to short circuit (because it is ideal diode).Now analyze the variation of Vo.It is clear that And because Vi varies sinusoidally, so Vo also varies sinusoidally. Step 3 : Now analyze the circuit with negative half cycle The next step is to check the condition of diode i.e., whether the diode is forward bias or reverse bias.In the circuit shown above it is clear that the diode is reverse bias and hence equivalent to open circuit (because it is ideal diode).Now analyze the variation of Vo.It is clear that Step 4: Now combine these two waveform.
What is the disadvantage of gunn diode?
Gunn Diodes are used in high frequency electronics. The advantages are increased efficiency and improved temperature stability while a disadvantage is the Gunn Diode can get burned out.
Am demodulator diode detector circuit pdf?
diode detector for am demodulation
Infinite resistance in one direction of Diode?
After isolating the diode from the circuit, the diode shows infinite resistance in one direction and low resistance in the other direction. The diode
Characteristics of diode clipper circuits?
clipper
How does the cut in voltage effects the output of a diode clipper?
For answering this question we have to consider the constant voltage drop model of the diode which says that if voltage across diode is less then its cut in voltage than assume diode to be open circuit and if it is greater then assume diode to be short circuit.Till the input voltage is less than the cut in voltage, diode is open circuit(thus no current through the circuit). Thus entire input voltage appears across the diode as output.When input voltage is greater than or equal to cut in voltage, then short circuit the diode. Thus, there will be no voltage drop across the diode as output.Thus cut in voltage decides when to consider the diode open circuit and when short circuit. It decides when the diode will have output when it will not.
What is clipper in electronic devices and circuit?
clipper is an AC application of diode. The Clipper clipps off a portion of the input signal waveform without distorting the remaining part of the alternating waveform. We can use different type of alternating waveforms as input such as sinusoidal, Triangular, square etc. There are different types of clippers e.g. series clipper, parallel clipper etc. but the method for solving all the type of circuits are same. So there is no need to remember the procedure for one particular clipper circuit. There are different types of clippers e.g. series clipper, parallel clipper etc. but the method for solving all the type of circuits are same. Now let us discuss the procedure with the help of a problem. Suppose we have given a clipper circuit shown below: Because clipper is an AC application of diode. So we apply an AC signal at the input Vi. Our aim is to find out the waveform of Vo. The solution steps are: Step 1 : First of all analyze the circuit by bifurcating the input waveform in positive half cycle and negative half cycle.Step 1.1 : Positive half cycle : Positive half cycle is equivalent to a battery of positive polarity and variable potential.Step 1.2 : Negative half cycle : Negative half cycle is equivalent to a battery of negative polarity and variable potential. Step 2 : Now analyze the circuit with positive half cycle.The next step is to check the condition of diode i.e., whether the diode is forward bias or reverse bias.In the circuit shown above it is clear that the diode is forward bias and hence equivalent to short circuit (because it is ideal diode).Now analyze the variation of Vo.It is clear that And because Vi varies sinusoidally, so Vo also varies sinusoidally. Step 3 : Now analyze the circuit with negative half cycle The next step is to check the condition of diode i.e., whether the diode is forward bias or reverse bias.In the circuit shown above it is clear that the diode is reverse bias and hence equivalent to open circuit (because it is ideal diode).Now analyze the variation of Vo.It is clear that Step 4: Now combine these two waveform.
How does diode acts as a circuit element?
Allows 1 way current/voltage flow
Can a diode power a circuit?
An ordinary diode, no. It has nowhere to get energy from.But a solar cell is a type of diode that converts light to electricity. So it is a diode that can power a circuit. So yes, there is one type of diode that can power a circuit.
What is the purpose of the diode in the GM AC clutch circuit?
The purpose of the diode is to prevent electricity to flow in the wrong direction in a circuit. The purpose of the diode is to prevent electricity to flow in the wrong direction in a circuit.
Why clipper circuit is use?
A: SIGNAL could overshoot a value which can damage the input or output therefore a diode is used to clip these signals to a safe level
What is the disadvantage of gunn diode?
Gunn Diodes are used in high frequency electronics. The advantages are increased efficiency and improved temperature stability while a disadvantage is the Gunn Diode can get burned out.
Am demodulator diode detector circuit pdf?
diode detector for am demodulation
What is the disadvantage and advantage of photo diode and transistor?
photo diode donot work for long distance photo diode act as a receiver
Why UJT's equivalent circuit has a diode?
A UJT is a special type of diode with a long resistive base having 2 contacts and acting as a voltage divider. The diode junction is created at a point on this base selected to set the trigger voltage of the UJT at which it will conduct. Therefore the equivalent circuit has a diode because the actual circuit has a diode.
Diode reverse breakdown14v current of 70mA and an un-stabilised supply voltage of 28v calculate resistance?
If a circuit element has a voltage of 14V and a current of 70mA, then the resistance of the circuit element is 200 ohms. This is ohm's law. The resistance or type of the power supply is meaningless.
