no
In a Silcon diode no current flows in the forward direction (anode to positive voltage) until approximately 0.6 - 0.7Volts is reached. Above this voltage the current rises in line with Ohms Law. In the reverse direction only micro Amps flow (leakage current) In a Germanium diode the threshold is about 0.2 volts and reverse leakage is higher.
Current
Ohms law does not consider inductance
Diode & Thermsistor
1 volt applied across one ohms Will conduct one Ampere
See OHMS LAW on the internet with a search engine. It will explain everything.
the resistance of a diode is .4 ohms is made of tantalum or .7 ohms if made of silicon. ANSWER: THE RESISTANCE OF A DIODE IS SIMPLY V/I the impedance however is defines by Boltzmann constant
ohms law.
If you are talking about reverse biasing a diode, then you are talking about a zener diode. A zener diode, like a normal diode, has a forward bias around 0.7 volts (depending on current and temperature). Using Ohm's law, you can calculate the effective resistance of the diode in forward bias. (Example: 0.7 volts, 100 milliamps, 7 ohms) In reverse bias, however, a zener diode conducts at a different voltage. This is what zener diodes do. Using Ohm's law, you will get a different effective resistance of the diode in reverse bias, because it is dropping a different voltage. (Example: 5.6 volts, 100 milliamps, 56 ohms) It should be noted that attempting to measure the resistance of a diode does not make sense, because it is a non linear device. You should instead consider the current to voltage curve to understand the diode, be it regular or be it zener.
In a Silcon diode no current flows in the forward direction (anode to positive voltage) until approximately 0.6 - 0.7Volts is reached. Above this voltage the current rises in line with Ohms Law. In the reverse direction only micro Amps flow (leakage current) In a Germanium diode the threshold is about 0.2 volts and reverse leakage is higher.
To find the conductance using ohms law,you take the inverse of the resistance(/R)
Current
No.
no
There is not enough information to answer this question correctly. As the current increases through a diode, the voltage dropped across it increases. This correlation is not a linear function such as a resistance, and a datasheet for the diode or a curve tracer would be necessary to obtain the correct function. To explain further, if there were 25 series LEDs all with a 3 volt drop across them, a 75 volt potential would be measured across the diodes, and 45 volts would be measured across the 5000 ohm resistor. Ohms law will show that 45 volts applied to 5K ohms will equal 9mA. This violates the 20mA criteria in the question.
ohms=amps/volts Amps= volts/ohms Volts = Amps*Ohms
Diode & Thermsistor