Thévenin's theorem for linear electrical networks states that any combination of voltage sources, current sources, and resistors with two terminals is electrically equivalent to a single voltage source V and a single series resistor R #wikipedia
actually i will explain you the way to solve problems applying this theorem consider a large network and in that network assume any resistance R about which you are asked o find the current and voltage-drop. now follow the steps below carefully
1. remove the specific resistor from the circuit (open the resistor) and find the voltage across both the points(or even parallel to both the points) where the resistor is opened this is called VTH (this is called thevenin's voltage).Also dont forget to open the current sources if present.
2. now to calculate the effective resistance as seen from the opened resistor short all the voltage sources and open all the current sources. and assume an arbitrary voltage V in the place of the opened resistor find current through the branch by mesh analysis and the ratio of voltage and current gives you the effective resistance fo the circuit as seen from the opened resistor. this is called Rth (thevenin resistance).
now , after getting the values of VTH,RTH construct a circuit in which the given resistance R and RTH arein series with the voltage source VTH , and the so called found current is the current flowing through R in the actual circuit
Ohm's Law and Kirchhoff's Laws allow solution of complex circuits, but they do not solve complex supplies.
If a supply contains multiple voltages or currents, or multiple resistances (or both), use Thévenin's ("tay-ven-ins") theorem:
"Any combination of voltage sources, current sources and resistors with two terminals is electrically equivalent to a single voltage source V and a single series resistor R."
no thevenins theorem works for every type of element. for a.c. analysis of a circiut consisting of capacitors inductors etc. a different method is followed to find thevenins equivalent but it is valid...
in simplifying complex circuits and for different loads this theorem proven very useful
yesAnswerNo it cannot, any more than Ohm's Law can be applied to circuits with non-linear elements.
Millman's theorem
Millman's theorem
thevenins theorem is applicable to network which is linear ,bilateral
no thevenins theorem works for every type of element. for a.c. analysis of a circiut consisting of capacitors inductors etc. a different method is followed to find thevenins equivalent but it is valid...
in simplifying complex circuits and for different loads this theorem proven very useful
lemma
yesAnswerNo it cannot, any more than Ohm's Law can be applied to circuits with non-linear elements.
The number of vehicles per hour entering a busy road junction equals the number leaving it The amount of liquid entering a pipe equals the amount issuing from the end, plus the leaks.
The theorem is a2+b2=c2 To explain, the legs of a triangle are labeled with a and b, but it doesn't matter which leg is labeled with which letter. The hypotenuse is always labeled with c. The theorem is that the sum of the two leg lengths squared is the square of the hypotenuse.
Postulate, Corollary, Definition, & Theorem
Pythagoras' theorem states that for any right angle triangle its hypotenuse when squared is equal to the sum of its squared sides.
Yes- provided its proof does not depend on the result you are using it to prove.
yes it only apllies to the right triangle and "c" is the hypotnuse of the triangles
the easiest thing to know it A squared + B squared = C squared