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Explain why an electric bulb becomes dim when an electric heater in parallel circuit is made onWhy dimness decreases after some time?
Wiki User
∙ 14y ago
this happen due to sudden amount of voltage drop in the main feeder due to large current drawn by the heater , so this drop in voltage will let the bulb operate by avltage of a mount (V-Vd) [where V represent the supply voltage and Vd represent the voltage drop in the main feeder of the circuit] , which is less than the voltage before the heater is connected and due to this situation the current passes through the wire of the bulb will be less and therefore the brightness of the bulb becomes dim.after a while the wire of the heater will has high temperature which increase its resistance and due to this the current drawn by the heater will decrease than the current at the first time , therefore the drop in voltage will also decrease , which implise increase in current drawn by the bulb and therefore the dimness decrease .
Wiki User
∙ 14y ago
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If at battery,parallel circuit shorts then equivalent resistance of circuit becomes approximately 0 Ohms,and therefore as current follows low resistance path infinite amount of current due to low resistance will flow through the wire so,entire parallel circuit will short out,but wire will burn and battery may get damaged. Name:Sumit Karnik.
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