This theorem is used to determine the value of current in specific branch of a multi voltage source circuit .
superposition can find the voltage and current effect of each source to a particular branch of the circuit and we can calculate the total effect of the sources to know the effect of the total sources to that branch
we cant consider two source at a time in superposition theorem....but power =v*i.so we cant calculate power.
Superposition theorem is one of those strokes of genius that takes a complex subject and simplifies it in a way that makes perfect sense. A theorem like Millman's certainly works well, but it is not quite obvious why it works so well. Superposition, on the other hand, is obvious.The strategy used in the Superposition Theorem is to eliminate all but one source of power within a network at a time, using series/parallel analysis to determine voltage drops (and/or currents) within the modified network for each power source separately. Then, once voltage drops and/or currents have been determined for each power source working separately, the values are all "superimposed" on top of each other (added algebraically) to find the actual voltage drops/currents with all sources active.
The equivalent of an inactive Thevenin voltage source is a source with zero voltage between its terminals regardless of the current through it, best represented by a zero resistance, i.e. a short-circuit. The equivalent of an inactive Norton current source is a source through which no current can flow regardless of the voltage across it, best represented by an infinite resistance, i.e. an open circuit.
superposition therorem states that in linear network containning more than one source of emf the resultant current in any branch is the algebraic sum of the current that would have been produced by each source of emf .taken sepertely with all other sources of emf replace by their internal resistance ........... that is called superposition theorem ..
You short a voltage source when doing this analysis because you do not know how much current will flow through the voltage source - consider it an undefined value. For the same reason, you open a current source since you know how much current will be flowing through it. This is a simple explanation; I'm sure a more exhaustive, technical one could be made if this is not sufficient.
The superposition theorem for http://www.answers.com/topic/electrical-network states that the response (Voltage or Current)in any branch of a bilateral linear circuit having more than one independent source equals the algebraic sum of the responses caused by each independent source acting alone, while all other independent sources are replaced by their internal http://www.answers.com/topic/impedance-1.
In circuits with multiple sources. This allows you to analyze the effects of each source separately, which often simplifies the math.
A: by using thevenin theorem
For a dependent source the main problem occurs while finding the equivalent impedance of the circuit . For this case : 1. Keep the dependent source as it is . 2. Apply a dc voltage across the o/p terminal . let it be Vdc 3. Let the current for this Vdc voltage source is Idc . 4. Find Zeq=Vdc / Idc. [Zeq is the equivalent impedance] [ Specially for superposition: we perhaps need not required the 2nd,3rd& 4th step . As we just have to calculate the current through the o/p . And , i think the dependent source should not be switched off any time . ]
1.Put a short circuit instead of voltage source 1 and find what you want with taking direction of current in that element(ris.ind.cap.) 2.puta short circuit instead of voltage source 2 and find what you want with taking direction of current in that element(ris.ind.cap.) 3.add current 1 and 2 for any element.