If, for example, the reactive power of a load is due to its inductance, then installing a capacitor in parallel with the load will reduce the overall reactive power.
A watt meter will measure active power, not reactive power.
Apparent power is the vectorial sum of the true power and reactive power. In this case, the total reactive power is the difference between 7200 var and 3600 var -i.e. 3600 var.So you can now use the equation,(apparent power)2 = (true power)2 + (total reactive power)2,to determine your answer.
In case of dc there is no reactive components and current drawn from the supply is in phase with the voltage.due to absence of inductor and capacitor the reactive power demand in dc is zero.
fugal
current that does't use in power measurement is called reactive current.
it should be done in order to reduce the power factor.
Actually reactive power is a power which flows in between load to source which is a reactive action of the power given from source to load.the given power to load will not be utilised fully.some power will be oscillating from load to source.this is called reactive power.
Inductors are considered to be a load for reactive power, meaning that they will draw reactive power from the system. Capacitors are considered to be sourced of reactive power, they feed reactive power into the system. If you have a circuit that is at unity (balanced with inductors and capacitors) no reactive power will be drawn from the source. You will have unity power factor. If your circuit is more inductive than capacitive it will be drawing reactive power from the source. The opposite is also true for capacitors.
Basically an AC transmission line require compensation in terms of reactive power. To push the active power across a transmission line certain amount of reactive power is necessary. In AC transmission line reactive power is generated and consumed. Generator is responsible for the production of reactive and active power both. Than this reactive power is consumed by the load and transmission line. Additional reactive power s supplied by the capacitor. This extra power supplied by the capacitor is termed as reactive power compensation. Requirement of this reactive power is there because reactive power is necessary to maintain the voltage stability.
A watt meter will measure active power, not reactive power.
Hi, Under excitation - inductive reactive power Over excitation - Capacitive reactive power.
No. It is apparent power (expressed in volt amperes) that is the combination (vector sum) of true power (expressed in watts) and reactive power (expressed in reactive volt amperes). 'Imaginary power' is simply another name for 'reactive power' -where 'imaginary' is simply mathematicians-speak for 'quadrature' or 'right angles'.
I am not sure what exactly you mean by "reactive power" (I guess you mean electrical reactive power), but power is the ratio of energy for a period of time. So that makes power (and reactive power as well) a scalar, since you can describe it with only one number. The fact that electrical reactive power is drawn on a XY plane, should not confuse you.
Use a wattmeter, as it only reads 'real power' of your load. Use an ammeter and a voltmeter, and the product of the two readings will give you 'apparent power' of your load. Since apparent power is the vector sum of real power and reactive power, use the following equation to find the reactive power of your load: (reactive power)2 = (apparent power)2 - (real power)2
Per factor is 1 when reactive power is zero.
To supply the reactive power demand of load and to regulate of output volage at the grid
Industrial users are charged extra if they have a poor power factor with a lot of reactive power being drawn. This is because they draw more current than necessary from the supply system, producing higher transmission losses in the resistance of the supply wires, and they are penalised by the supply company to encourage them to improve their power factor. Reactive power can be removed by the user using the right equipment, thus reducing the supply charges. Electric motors are a common source of reactive power and large electric motors are provided with power-factor correction to bring the power factor up to 0.85. This is done by using capacitors in parallel with the supply to draw reactive power of the opposite kind. As an example, a 100 kW motor with a PF of 0.7 would draw 140 kVA from the supply (because 140 x 0.7 is 100). This contains 100 kVAr of reactive power (because 1002 + 1002 = 1402) and a capacitor would be added to draw 100 kVAr of negative reactive power. This would reduce the load to 100 kW with a power factor of 1. Another way to look at this is that the added capacitor forms a tuned circuit with the motor, that resonates at the supply frequency.