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How do I design a voltage divider circuit that has 2 VDC 5 VDC and 8 VDC available with a 10 VDC source?
Wiki User
∙ 9y ago
Without knowing permissible current draw by the divider or its maximum power dissipation the actual resistor values cannot be determined, but the ratios of the resistor values can be determined from the required voltage drops.
The divider will be composed of 4 resistors starting at the 10VDC rail:
- 2VDC drop, ratio = 2V/10V = 0.2
- 3VDC drop, ratio = 3V/10V = 0.3
- 3VDC drop, ratio = 3V/10V = 0.3
- 2VDC drop, ratio = 2V/10V = 0.2
Therefore you will need 2 resistors (R1 & R4) that are 0.2 * the total resistance of the voltage divider and 2 resistors (R2 & R3) that are 0.3 * the total resistance of the voltage divider.
But as stated at the beginning you can get no further without additional requirements being specified.
Wiki User
∙ 9y ago
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