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It is simple LEDS do need a definite voltage drop to work must have a minimum current to operate. for a 9v battery source and a LED of 3.2v operating at 20ma the solution will be 9v-3.2=5.8v therefore to limit the current to 20ma a resistor of 5.8v/0.02=290 ohms not such an animal so a 270-300 ohms will work. Final note make sure that the LED power is not exceeded 3.2v x0.02ma=63 mw

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14y ago
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Q: How do you make a led simple circut?
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