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Assuming that the figures you supply in your question are line values, and not phase values, and each line current is identical, then you can find the total apparent power (in kV.A ) by applying the following equation:

apparent power = 1.732 VL IL

If, then, by 'per leg', you mean 'per phase', then all you need to do is to divide your answer by 3.

Incidentally, the correct symbols are 'kV.A', not 'kva', 'V' not 'v', and 'A' not 'amp'. lin

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