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A unit, short for 'Board of Trade unit', is used to measure energy and is exactly equivalent to a kilowatt hour.

When a motor is described as being rated at, say, 0.75 horsepower, what is being described is its output power or the rate at which it is supplying energy to its mechanical load. So, it's necessary to determine what the input power (which is greater than its output power) is and, to do this, you need to know its efficiency.

If we assume that the efficiency of the motor is, say, 85% at its rated output, then the input power will be (0.75 x 746) / 0.85 = 658 watts. The amount of energy supplied to the motor, therefore, will be (658/1000) x 1 = 0.658 kilowatt hours.

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Q: How many units of electricity does 0.75HP motor consumes per hour?
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