Let C1=0.05F
& C2=0.025F, C1 & C2 are in series
Let the equivalent capacitance will be C
than 1/C = 1/C1 + 1/C2
1/C = 1/0.05 + 1/0.025 = 20 + 40 = 60F
hence C= 1/60 = 0.0166667 F
Total parallel capacitance is the sum of the value of the parallel capacitors. It uses the formula - Total Capacitance = C1 + C2 + C3. Hopefully, you can do the math at this point.
the charge on the capacitor had increased.
A capacitor is placed across the supply of a fluorescent lamp circuit to correct the power factor
No, an ammeter should never be placed in parallel with a component - it should always be placed in series, so that the current through the component is measured.If you place an ammeter in parallel with a component, you create a short circuit around the component. Depending on the rest of the circuit, you could damage the circuit, damage the ammeter, create a fire, etc. You certainly will affect the current through the component, and that is not what you want to accomplish.
This capacitor carries a current of 25,000/690 or 36.2 amps and its impedance (reactance) is 19 ohms. The capacitance is 1/(2.pi.50.19) or 0.000167 Farad, on a 50 Hz system. The time-constant is CR so that if a 20,000 ohm resistor is placed across the capacitor the time-constant is 3.3 seconds. The voltage is reduced by 99% after 5 time-constants or in this case 17 seconds. If the discharge resistor is permanently in circuit it dissipates 690^2 / 20000 or 24 watts.
capacitance will tend to zero
Total parallel capacitance is the sum of the value of the parallel capacitors. It uses the formula - Total Capacitance = C1 + C2 + C3. Hopefully, you can do the math at this point.
Definitely not possible. Capacitance is given by an expression C = epsilon x A / d Since charge is not present the capacitance cannot be increased or decreased by the charge placed
A cylindrical capacitor is a type capacitor in which two conducting cylinders are used and the dielectric medium is placed in between them .The outer most cylinder is earthed .The capacitance of these capacitors are higher than other
when we replace the resistor with a capacitor ,the current will flow until the capacitor charge when capacitor will fully charged there is no current through the circuit because now capacitor will act like an open circuit. for more info plz E-mailt me at "zaib.zafar@yahoo.com"
Eventually, the capacitor will charge to approximately the source voltage level. As this occurs, the current in the circuit will drop to near zero.
A starting cap is placed in circuit of the start windings only when the motor is starting and is normally of a higher capacitance than a running cap, in the region of 70 - 120 mf, where a running cap stay connected with the start windings of the motor and is normally an 8 mf cap.
Type your answer here... As per the definition of capacitor it is a device which made up of dielectric material in between two parallel metal plates. Even two metal plates placed parallel in open area will result in capacitance since air is also dielectric in nature..
the charge on the capacitor had increased.
A capacitor is placed across the supply of a fluorescent lamp circuit to correct the power factor
A trimmer capacitor is a semi-adjustable capacitor placed across a variable tuning capacitor and pre-set to allow the main capacitor to track correctly with another variable capacitor on the same shaft. The adjustment takes out any differences introduced by the connected circuit.
um.. a switch is a part of a series circuit because parallel circuits don't have switches