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Ummm, are you asking for the function fc= 1/square root (2 pi c r)? ya m asking for this but how can i derive this by taking the resonant frequencyconcept you takethe resistance offered by an resistsance is equal to resistance offered by capacitor =>r=1/wc =>w=1/rc =>2 pi f=1/rc =>f=

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Q: Low pass RC filter cut-off frequency derivation?
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The cutoff frequency of filter depends upon the value of capacitor and resistance. Therefore, below cutoff frequency or above this frequency, capacitor allow to pass all other frequencies.


How does a capacitor acts as a filter?

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