The answer depends entirely upon the scenario. Are you dealing with AC or DC? Does your circuit contain passive components or both passive and active components?
For example, if you a simply dealing with a resistive DC circuit, you can derive your answer from Ohm's law, V = IR. Rearranging for current, I = V/R, so if you double the voltage, the current is subsequently doubled.
resistance is directly proportional to wire length and inversely proportional to wire cross-sectional area. In other words, If the wire length is doubled, the resistance is doubled too. If the wire diameter is doubled, the resistance will reduce to 1/4 of the original resistance.
The circuit resistance is likely to gradually drop and in such case it will cause the circuit to burn down.
It shortens
P1 = V I1, Therefore, if P2=0.5*P1, thenI2=0.5*P1/V, or 0.5*I1and if P3=2*P1, thenI3=2*P1/V, or 2*I1In other words, current is proportional to power and inversely proportional to voltage.
Yes, if the resistance remains constant. Power is voltage times current, and current is voltage divided by resistance, so power is voltage squared divided by resistance. In essence, the power increases as the square of the voltage.
It is halved. coz voltage=current * resistance
In a parallel circuit, the total resistance remains the same when the voltage applied is doubled. Each branch in the parallel circuit will experience the same increase in voltage, but their individual resistances will remain constant.
When the frequency is doubled, the resistance of a circuit remains unchanged. Resistance in a circuit is independent of frequency and is determined by the material and physical dimensions of the resistor.
When the voltage in a circuit is doubled, the current typically increases, assuming the resistance remains constant according to Ohm's Law (V = IR). If resistance is unchanged, doubling the voltage will result in doubling the current. However, if the circuit components have nonlinear characteristics, the actual change in current may vary. Always consider the specific characteristics of the circuit for precise outcomes.
If the voltage is doubled and the resistance is constant, Ohm's Law states that the current will also double. This is because the relationship between voltage, current, and resistance is linear, and increasing the voltage will directly increase the current flow.
Since resistance is the ratio of voltage to current, we can say that halving the resistance will result in twice the current.
If the voltage in a circuit is kept constant and the wire diameter is increased, the resistance of the wire decreases. According to Ohm's Law (I = V/R), where I is current, V is voltage, and R is resistance, a decrease in resistance results in an increase in current. Therefore, with a larger wire diameter, more current will flow through the circuit at the same voltage.
Using Ohms Law: V = I x R, where V (Voltage), I (Current), and R (Resistance). re-arranging: V/R = I Therefore if you double both the Voltage and the Resistance, the current remains unchanged.Current = Voltage / Resistance. If both resistance and voltage double the current remains the same.
If you add a second resistor, the resistance of series circuit will increase.
resistance is directly proportional to wire length and inversely proportional to wire cross-sectional area. In other words, If the wire length is doubled, the resistance is doubled too. If the wire diameter is doubled, the resistance will reduce to 1/4 of the original resistance.
The circuit resistance is likely to gradually drop and in such case it will cause the circuit to burn down.
When you add resistance to a circuit, current goes down. Ohm's Law: current = voltage divided by resistance.