Node is Actually is nothing you can consider its as point where the Current (Ampere) Actually Get Distributed in Two or more ways .. where every get current divided that point will be know as Node
It is the ground node. You need to find all extraordinary nodes when using node-voltage analysis; choose one to be ground. It can be selected arbitrarily.
Kirchhoff's Current Law
"Electronics" is an engineering discipline or field of study or endeavour, as in "I Studied Electronics at MIT". "Electronic" is an adjective, as in "Electronic Calculator". An engineer working in this field can be described as either an "Electronics Engineer" or an "Electronics Engineer".
yes
It is a juncture of 2 or more electrical devices.
NC on a schematics typically stands for "No Connection" meaning that nothing is to be connected to that node.
_node* search (_node* head, _key key) { _node* node; for (node=head; node != NULL;;) { if (key == node->key) return node; else if (key < node.>key) node = node->left; else node = node->right; } return node; }
for (node=head; node!=null; node=node->next) printnode(node);
Refer to http://cslibrary.stanford.edu/110/BinaryTrees.html void mirror(struct node* node) { if (node==NULL) { return; } else { struct node* temp; // do the subtrees mirror(node->left); mirror(node->right); // swap the pointers in this node temp = node->left; node->left = node->right; node->right = temp; } }
Yes. The tail node's next node is the head node, while the head node's previous node is the tail node.
Given a list and a node to delete, use the following algorithm: // Are we deleting the head node? if (node == list.head) { // Yes -- assign its next node as the new head list.head = node.next } else // The node is not the head node { // Point to the head node prev = list.head // Traverse the list to locate the node that comes immediately before the one we want to delete while (prev.next != node) { prev = prev.next; } end while // Assign the node's next node to the previous node's next node prev.next = node.next; } end if // Before deleting the node, reset its next node node.next = null; // Now delete the node. delete node;
It depends on the context. If in the context of Wireless Internet, which certainly involves analog electronics, a "wireless mesh network" is a network that relies on all nodes to propogate signals. If it is lumped element circuit theory you have in mind, the "node method" and "mesh method" of circuit analysis both apply Kirchoff's Laws to analyze a circuit. The idea behind either method is to simplify the application of these laws, to come up with a method simpler than brute force solution of a system of linear equations. In the node method, a 'node' is a reference point chosen to have 0 potential; in the mesh method, a 'mesh' is a closed current loop not containing any other loop. Google "mesh node method circuit analysis" for lots of references supplying the details of either method.
No. A leaf node is a node that has no child nodes. A null node is a node pointer that points to the null address (address zero). Since a leaf node has no children, its child nodes are null nodes.
An intrathoracic node is a node within the chest cavity.
For a singly-linked list, only one pointer must be changed. If the node about to be deleted (let's call it node for the sake of argument) is the head of the list, then the head node pointer must be changed to node->next. Otherwise, the node that comes before the deleted node must change its next pointer to node->next. Note that given a singly-linked node has no knowledge of its previous node, we must traverse the list from the head in order to locate that particular node, unless the node is the head of the list: void remove (List* list, Node* node) { if (!list !node) return; // sanity check!if (list->head == node) {list->head = node->next;} else {Node* prev = list->head;while (prev->next != node) prev = prev->next; // locate the node's previous nodeprev->next = node->next;}} Note that the remove function only removes the node from the list, it does not delete it. This allows us to restore the node to its original position, because the node itself was never modified (and thus still refers to its next node in the list). So long as we restore all removed nodes in the reverse order they were removed, we can easily restore the list. In order to delete a node completely, we simply remove it and then free it:void delete (List* list, Node* node) {if (!list !node) return; // sanity check!remove (list, node);free (node);} For a doubly-linked list, either two or four pointers must be changed. If the node about to be deleted is the head node, then the head node pointer must be changed to n->next and n->next->prev must be changed to NULL, otherwise, n->prev->next becomes n->next. In addition, if the node about to be deleted is the tail node, then the tail node pointer must be changed to n->prev and n->prev->next must be changed to NULL, otherwise, n->next->prev becomes n->prev. Deletion from a doubly-linked list is generally quicker than deletion from a singly linked list because a node in a doubly-linked list knows both its previous node and its next node, so there's no need to traverse the list to locate the previous node to the one being deleted. void remove (List* list, Node* node) {if (!list !node) return; // sanity check!if (list->head == node) {list->head = node->next;node->next->prev = NULL;} else {node->prev->next = node->next; }if (list->tail == node) {list->tail = node->prev;node->prev->next = NULL;} else {node->next->prev = node->prev; }} Again, to physically delete the node we simply remove and then free the node:void delete (List* list, Node* node) {if (!list !node) return; // sanity check!remove (list, node); free (node); }
cardiopulmonary node
The primary pacemaker of the mammalian heart is the sino-atrial node. If the SA node fails, the atrioventricular node (AV node) takes over pacemaking.