Sometimes it isn't.
Another Answer
Voltage drops don't have polarity in the sense of a positive or negative charge. The term 'polarity', when applied to voltage drops, describe the sense or the direction in which that voltage drop is acting within the circuit. The rule is that a voltage drop always acts in the opposite direction to the current which causes it. An example of when it's necessary to know the polarity (direction) of a voltage drop is when applying Kirchhoff's Laws or other network theorems to solve a circuit
In a d.c. circuit, voltage drop is the product of resistance and current through that resistance.
in case of ideal voltage source we consider the internal resistance to be zero.but in practical,every battery has some internal resistance then if you connect a load resistance across the terminals of that source,the net potential difference's across the voltage source will be a function of external resistance connects it won't give constant voltage across it's terminals.
Ohm's law states that the voltage across a resistor is the product of the current times the Resistance or V=I x R (I times R). V is Voltage, R is Resistance, and I is Current or Amperage. So if the Voltage is doubled and Resistance stays the same, the Current will be doubled.
The reason an AC voltage applied across a load resistance produces alternating current is because when you have AC voltage you have to have AC current. If DC voltage is applied, DC current is produced.
The current through each resistor is equal to the voltage across it divided by its resistance for series and parallel circuits.
IR drop across a resistance is voltage. The letter I means current, and the letter R means resistance. Current times resistance, by Ohm's law is voltage.
In a d.c. circuit, voltage drop is the product of resistance and current through that resistance.
The voltage across each series component is proportional to its resistance, and their sum is equal to the voltage between the ends of the complete series string.
A: by using thevenin theorem
in case of ideal voltage source we consider the internal resistance to be zero.but in practical,every battery has some internal resistance then if you connect a load resistance across the terminals of that source,the net potential difference's across the voltage source will be a function of external resistance connects it won't give constant voltage across it's terminals.
There are two ways of looking at this question, depending on what you mean by 'voltage'.The first applies to the supply voltage, which is quite independent of a circuit's load resistance. In other words, changing the load resistance will have no effect on the supply voltage (within limits; for example, and extremely-low resistance might cause the supply voltage to collapse!).The second applies to any voltage drops, which are proportional to the resistance across which they appear. If, for example, you have a high resistance and a low resistance, in series, then the higher voltage drop will appear across the higher resistance.
Ohm's law states that the voltage across a resistor is the product of the current times the Resistance or V=I x R (I times R). V is Voltage, R is Resistance, and I is Current or Amperage. So if the Voltage is doubled and Resistance stays the same, the Current will be doubled.
As the resistance is reduced across the same voltage, the current increases.
By Ohm's Law, current is voltage divided by resistance, so if you double both the voltage and the resistance, the current would remain the same.
The reason an AC voltage applied across a load resistance produces alternating current is because when you have AC voltage you have to have AC current. If DC voltage is applied, DC current is produced.
Resistance.
The amount of current that will pass through a resistance is dependant upon the voltage applied across the resistance. Voltage devided by resistance equals current. This is Ohm's Law.